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Mrac [35]
4 years ago
12

Compare and contrast absolute dating and relative dating.

Chemistry
2 answers:
ankoles [38]4 years ago
8 0

Answer:

Absolute dating is based on calculations of the age of rock strata based on half lives of minerals, relative dating is based on the assumed age of fossils found in the strata and the laws of super imposition.

Explanation:

PilotLPTM [1.2K]4 years ago
3 0

Answer:

Absolute dating and relative dating are both methods used to determine the age of a fossil. Absolute dating gives the actual age of a fossil in years based on the amount of radioactive and stable elements in the fossil. Relative dating gives an estimate of the age of a fossil based on the location of the fossil in relation to other fossils.  

Explanation:

sample response

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Which best explains the difference between a monomer and a polymer?
Rainbow [258]
All monomers have the capacity to form chemical bonds to at least two other monomer molecules. Polymers are a class of synthetic substances composed of multiples of simpler units called monomers.
7 0
3 years ago
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A solution of a base differs from a solution of an acid in that the solution of a base?A. is able to conduct electricity B. is a
Anon25 [30]

Answer:

  • <u><em>Option D. has a great [OH⁻]</em></u>

Explanation:

1) Both <em>acids</em> and <em>bases</em> ionize in aqueous solutions so they are able to <em>conduct electricity</em>.

The ions, being charged particles, when flow through the solution are charge carriers, then they conduct electricity.

So, the option A does not state a difference between a solution of a base and a solution of an acid.

2) Both acids and bases are able to cause an <em>indicator color change</em>.

The usufulness of the indicators is that they are able to change of color when the pH changes either from acid to basic or from basic to acid. There are different indicators because none is suitable for the whole range of pH, but the statement B is not how solutions of base and acids differ.

3) The model of Arrhenius for acids and bases states that an acid is a substance that ionizes in water releasing H⁺ ions (this is equivalent to H₃O⁺) and a base is a substance that releases OH⁻ ions in water. Then, acids have a greater concentration of H₃O⁺ (so option C is not true for a solution of a base) and bases  have a greater concentraion of OH⁻, making the option D. true.

8 0
3 years ago
At a certain temperature, 0.740 mol of so3 is placed in a 4.00 l container. so_{3}(g)\rightleftharpoons 2so_{2}(g)+o_{2}(g) at e
Phoenix [80]

Answer : The equilibrium constant kc is 4.76 x 10⁻³

Explanation :

The given equilibrium reaction is

2SO_{3} (g) \leftrightarrow 2SO_{2} (g) + O_{2} (g)

Step 1 : Set up ICE table

Let us set up an ICE table for this reaction .

The initial concentration of SO₃ is

Concentration = \frac{mol}{L} = \frac{0.740mol}{4L} = 0.185 M

The initial concentrations of products are 0.

Let us assume x is the change .

Please refer the attached picture.

Step 2 : Use the given value to find x

From the ICE table, we can see that at equilibrium, concentration of O₂ is x

But we have been given that , at equilibrium we have 0.190 mol of O₂ .

Let us convert this to concentration unit.

Concentration of O₂ at equilibrium = \frac{mol}{L} = \frac{0.190mol}{4L} = 0.0475 M

But concentration of O₂ from the ICE table is x.

Therefore we have x = 0.0475 M

Step 3 : Using x , find equilibrium concentrations

Using this value, let us write the equilibrium concentrations of the given species.

[SO₃]eq = 0.185 M - 2x = 0.185 - 2(0.0475) = 0.09 M

[SO₂]eq = 2x = 0.095 M

[O₂]eq = x = 0.0475 M

Step 4 : Set up equation for kc and solve it

The equilibrium constant kc is calculated as,

k_{c} = \frac{[SO_{2}]^{2} [O_{2}]}{[SO_{3}]^{2}}

Let us plug in the above equilibrium values.

k_{c} = \frac{(0.095)^{2} (0.0475)}{(0.09)^{2}}

k_{c} = \frac{0.00042869}{0.09}

k_{c} = 4.76 \times 10^{-3}

The equilibrium constant kc is 4.76 x 10⁻³

3 0
3 years ago
HELP PLEASE! :( 
BabaBlast [244]

Answer:

Part 1: W = 116 Y = 163

Part 2: Since 232 is the mailing point of 2 kg then you would divide 232 by 2 to get the melting point for 1 kg, the same with Y.

6 0
4 years ago
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What is the conversion factor for in^3 to cm^3
DochEvi [55]
You multiply by 16.3871
5 0
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