Does anyone knows the answer to this?

Based on the fossil records, what is true

soldier1979 [14.2K]

Answer:

C

Explanation:

The reason why is beacause most of the dino's and other spices that were here before humanity are exctinct. Some are still alive and have evovled into something greater such as a crocidile, and many other repitlians

Hope this helps!

Pls mark brainlest!

8 0

3 years ago

If the volume of a substance is measured with a graduated cylinder, the unit of measure for volume will be:

nirvana33 [79]

Answer:Today they will practice measuring different liquids. They will use a container called a graduated cylinder to measure liquids. Graduated cylinders have numbers on the side that help you determine the volume. Volume is measured in units called liters or fractions of liters called milliliters (ml).

Explanation:

8 0

3 years ago

After 1911, most scientists accepted the theory that the nucleus of an atom was very dense and very small and had a positive cha

Scorpion4ik [409]

Answer:

I believe it is D

Explanation:

since Rutherford's explanation, when he made it in 1911, was that scattering was caused by a hard, dense court to centre of the Adam, which is the nucleus and he used Alpha particles to observe the scattered backwards from a gold foil

4 0

3 years ago

Calculate the concentration of OH in a solution that contains 3.9 10-4 M H30 at 25°C. Identify the solution as acidic, basic or

Norma-Jean [14]

Answer:

Option A) 2.6 × 10⁻¹¹ M, acidic.

Explanation:

The ion-product constant of water $K_{\rm w}$ gives a relationship between $\rm [H_3O^{+}]$ and $\rm [OH^{-}]$ :

$K_{\rm w} = \rm [H_3O^{+}]\cdot [OH^{-}]$ .

The exact value of $K_{\rm w}$ depends on the temperature. Under $\rm 25^{\circ}C$ , $K_{\rm w} \approx 1^{-14}$ .

The question states that $\rm [H_3O^{+}] = 3.9\times 10^{-4}\; M$ . As a result,

$\begin{aligned} {\rm [OH^{-}]} &= \frac{K_{\rm w}}{[{\rm H_3O^{+}}]}\\ &\approx\frac{1^{-14}}{3.9\times 10^{-4}} && \rm {\leftarrow Only~under~25^{\circ}C.}\atop{}\\&\approx \rm 2.6\times 10^{-11}\; M\end{aligned}$ .