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3 years ago

Which is a possible excited state configuration for Nitrogen?

Chemistry

1 answer:

nikklg [1K]3 years ago

3 0

I think the answer might be D or A

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A 1M solution is made of each item in a pair. When would this combination create a buffer? Chose the pairs below that you could

monitta

Answer:

b. HCOOH/ NaHCOO.

Explanation:

A buffer system may be formed in one of two forms:

A weak acid with its conjugate base.

A weak base with its conjugate acid.

Chose the pairs below that you could use to make a buffered solution.

a. HCI/NaOH. NO. HCl is a strong acid and NaOH is a strong base.

b. HCOOH/ NaHCOO. YES. HCOOH is a weak acid and HCOO⁻ (coming from NaHCOO) is its conjugate base.

c. HNO₂/H₂SO₃. NO. Both are acids and they are unrelated to each other.

d. NaNO₃/ HNO₃. NO. HNO₃ is a strong acid.

7 0

3 years ago

If 25.3 grams of mercury(II) oxide react to form 23.4 grams of mercury, how many grams of oxygen must simultaneously be formed?

sergij07 [2.7K]

Answer : The mass of oxygen formed must be 3.8 grams.

Explanation :

Law of conservation of mass : It states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

This also means that total mass on the reactant side must be equal to the total mass on the product side.

The balanced chemical reaction will be,

$2HgO\rightarrow 2Hg+O_2$

According to the law of conservation of mass,

Total mass of reactant side = Total mass of product side

Total mass of $2HgO$ = Total mass of $2Hg+O_2$

As we are given :

The mass of $HgO$ = 25.3 grams

The mass of $Hg$ = 23.4 grams

So,

$2\times 25.3g=2\times 23.4g+\text{Mass of }O_2$

$50.6g=46.8g+\text{Mass of }O_2$

$\text{Mass of }O_2=3.8g$

Therefore, the mass of oxygen formed must be 3.8 grams.

6 0

3 years ago

The arrows show the changes of state.

Romashka [77]

Answer:

condensation

Explanation:

when gases change to liqud it condenses.This occurs when the temperature is lowered

3 0

3 years ago

Which elements are considered metals? Non-metals? Metalloids?

kolbaska11 [484]

The answer is in the photo.

3 0

3 years ago

How many moles of oxygen are necessary to react completely with four moles of propane (CH)?

steposvetlana [31]

Answer:

20 mole of oxygen

Explanation:

1 mole of proprane reacts with 5 moles of oxygen so 4 time 5 equals 20

7 0

3 years ago