A mixture could be for example sand and water , it could be separated using filter paper. When the sand and water are poured through the filter paper they separate
Answer is: molarity of sodium hydroxide solution is 1.95 M.
m(NaOH) = 68.4 g.
n(NaOH) = m(NaOH) ÷ M(NaOH).
n(NaOH) = 68.4 g ÷ 40 g/mol.
n(NaOH) = 1.71 mol.
V(NaOH) = 875 mL ÷ 1000 mL/L = 0.875 L.
c(NaOH) = n(NaOH) ÷ V(NaOH).
c(NaOH) = 1.71 mol ÷ 0.875 L.
c(NaOH) = 1.954 mol/L.
The mass percent of sulfurous acid in the new solution : 38.9%
<h3>Further explanation</h3>
<em>In a container you have 800 g of a 35% by mass solution of sulfurous acid, from which 80 ml of water evaporates. What is the mass percent of sulfurous acid in the new solution? data: density of water is 1g / ml.</em>
<em />
solution 1
composition :
solution 2(new solution)
composition :
- Total mass of new solution after water evaporated
- %mass of acid in a new solution
The answer should be 'hotter' and 'cooler'
The hot water molecules would become less dense and thus rise above the denser cooler molecules.
Hope that helps!
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