How can magnetic force be exerted on objects?

Carry out some research into how new elements get their name and their symbols. Write out a short passage (no more than 50 words

spin [16.1K]

The IUPAC says that elements have to be named after one of five things: a scientist, a place, a mineral or substance, a descriptor of the element, or a mythological reference. Of the new elements, three are named after places and one is named after a person No-one has yet named an element after themselves but many elements are named in tribute to important scientists
(you can cut some stuff out)

6 0

2 years ago

I'm strong and stiff

Andreas93 [3]

Answer:

Sap?

Explanation:

6 0

2 years ago

The first 18 elements in the periodic table have which of the following important properties? a. They have the largest atomic nu

fenix001 [56]

d. These elements make up most of the matter of the known universe

7 0

2 years ago

Read 2 more answers

Calculate the amount of heat energy in KJ required to convert 45.0 g of ice at -15.5'C to steam at 124.0°C. (Cwater 118 Jig'c, G

dangina [55]

Answer : The enthalpy change or heat required is, 139.28775 KJ

Solution :

The conversions involved in this process are :

$(1):H_2O(s)(-15.5^oC)\rightarrow H_2O(s)(0^oC)\\\\(2):H_2O(s)(0^oC)\rightarrow H_2O(l)(0^oC)\\\\(3):H_2O(l)(0^oC)\rightarrow H_2O(l)(100^oC)\\\\(4):H_2O(l)(100^oC)\rightarrow H_2O(g)(100^oC)\\\\(5):H_2O(g)(100^oC)\rightarrow H_2O(g)(124^oC)$

Now we have to calculate the enthalpy change.

$\Delta H=[m\times c_{p,s}\times (T_{final}-T_{initial})]+n\times \Delta H_{fusion}+[m\times c_{p,l}\times (T_{final}-T_{initial})]+n\times \Delta H_{vap}+[m\times c_{p,g}\times (T_{final}-T_{initial})]$

where,

$\Delta H$ = enthalpy change or heat required = ?

m = mass of water = 45 g

$c_{p,s}$ = specific heat of solid water = $2.09J/g^oC$

$c_{p,l}$ = specific heat of liquid water = $4.18J/g^oC$

$c_{p,g}$ = specific heat of liquid water = $1.84J/g^oC$

n = number of moles of water = $\frac{\text{Mass of water}}{\text{Molar mass of water}}=\frac{45g}{18g/mole}=2.5mole$

$\Delta H_{fusion}$ = enthalpy change for fusion = 6.01 KJ/mole = 6010 J/mole

$\Delta H_{vap}$ = enthalpy change for vaporization = 40.67 KJ/mole = 40670 J/mole

Now put all the given values in the above expression, we get

$\Delta H=[45g\times 4.18J/gK\times (0-(-15.5))^oC]+2.5mole\times 6010J/mole+[45g\times 2.09J/gK\times (100-0)^oC]+2.5mole\times 40670J/mole+[45g\times 1.84J/gK\times (124-100)^oC]$

$\Delta H=139287.75J=139.28775KJ$ (1 KJ = 1000 J)

Therefore, the enthalpy change is, 139.28775 KJ

3 0

2 years ago

What is the mass in grams of oxygen gas that is required to produce 32.1 grams of maleic acid anhydride?

klemol [59]

Considering the reaction stoichiometry, the mass of oxygen gas that is required to produce 32.1 grams of maleic acid anhydride is 47.17 grams.

The balanced reaction is:

2 C₆H₆(l) + 9 O₂(g)→ 2 C₄H₂O₃(s) + 4 CO₂(g) + 4 H₂O(g)

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

C₆H₆: 2 moles
O₂: 9 moles
C₄H₂O₃: 2 moles
CO₂: 4 moles
H₂O: 4 moles

The molar mass of each compound is:

C₆H₆: 78 g/mole
O₂: 32 g/mole
C₄H₂O₃: 98 g/mole
CO₂: 44 g/mole
H₂O: 18 g/mole

By reaction stoichiometry, the following amounts of mass of each compound participate in the reaction:

C₆H₆: 2 moles× 78 g/mole= 156 grams
O₂: 9 moles× 32 g/mole= 288 grams
C₄H₂O₃: 2 moles× 98 g/mole= 196 grams
CO₂: 4 moles× 44 g/mole= 176 grams
H₂O: 4 moles× 18 g/mole= 72 grams

Then you can apply the following rule of three: If by stoichiometries 196 grams of C₄H₂O₃ are produced by 288 grams of O₂, 32.1 grams of C₄H₂O₃ are produced from how much mass of O₂?

$mass of O_{2} =\frac{32.1 grams of C_{4} H_{2} O_{3} x288 grams of O_{2}}{196grams of C_{4} H_{2} O_{3}}$

mass of O₂= 47.17 grams

Finally, the mass of oxygen gas that is required to produce 32.1 grams of maleic acid anhydride is 47.17 grams.

Learn more:

3 0

2 years ago