2HCl (aq) + Zn²⁺ ⇒ ZnCl₂ + 2H⁺ Total Reaction
Leo goes Ger (Lose electron oxidize, Gain electron reduction)
Zn²⁺ + 2e⁻ ⇒ Zn Oxidation half-reaction
2H ⇒ 2H⁺ + 2e⁻ Reduction half-reaction
Answer:
There is a 1:1 neutralization reaction, so, number of moles:
0.085 l * 0.900 mol/ L = 0.0765 mol HCL
The heat produced: 0.0765 mol * -56.2 kJ/mol = -4.229 kJ (this is the heat of neutralization)
Change in temperature: The mass to use in the equation Q=cmT.
4229 J / (4.186 J/gC*170 g) = 6.042 C
Add to the initial temperature:
18.24 + 6.042 = 24.29 C°
I believe its C because 7.5 would be considered a base and when acid it’s added it’s PH neutralizes the solution
You need to find the formula mass of NaCl first, which you find the amu of both sodium and chlorine on the periodic table and you add them both. Then you divide the 175.5g by the formula mass which I got 58 g to get 3.026 moles of NaCl. 4 sig figs because of the 175.5. I recommend doing it on your own to make sure you get the right answer. You divide the 175.5g of NaCl by the formula mass.
