Answer:
*a car geared neutral that is at a stop. two men start pushing it
*tire physical therapy. trie is at rest until you come up to the tire and flip it
*pushing a wheel barrel
Explanation:
everthing has to be at a complete stop then through energy be moved
Answer:
See the explanation below, please.
Explanation:
In redox reactions (oxide reduction) the transfer of electrons between compounds occurs.
In oxidation, electrons are lost (positive charge increases). Example:
Mg ---> Mg2 + + 2 e- (passes from Mg ° to Mg 2+)
On the other hand in the reduction, electrons are gained (negative charge increases or the positive one increases). Example:
Cl2 + 2e- ---> 2 Cl- + 2 e- (passes from Cl ° to Cl-)
Answer:
Ksp = [ Cu+² ] [ OH-] ²
molar mass Cu(oH )2 ==> M= 63.546 (1) + 16 (2) + 1 (2) = 97.546 g/mol
Ksp = [ Cu+² ] [ OH-] ²
Ksp [ cu (OH)2 ] = 2.2 × 10-²⁰
|__________|___<u>Cu</u><u>+</u><u>²</u><u> </u>__|_<u>2</u><u>OH</u><u>-</u>____|
|<u>Initial concentration(M</u>)|___<u>0</u>__|_<u>0</u>______|
<u>|Change in concentration(M)</u>|_<u>+S</u><u> </u>|__<u>+2S</u>__|
|<u>Equilibrium concentration(M)|</u><u>_S</u><u> </u><u>_</u><u>|</u><u>2S___</u><u>|</u>
Ksp = [ Cu+² ] [ OH-] ²
2.2 ×10-²⁰ = (S)(2S)²= 4S³
S = 1.8 × 10-⁷ M
The molar solubility of Cu(OH)2 is 1.8 × 10-⁷ M
Solubility of Cu (OH)2 =
<h3>
Solubility of Cu (OH)2 = 1.75428 × 10 -⁵ g/ L</h3>
I hope I helped you^_^
Hey there!
The best way to balance chemical equations is to first start by balancing polyatomic ions such as OH and SO₄.
Next, balance other elements, but save elements that are by themselves for last, such as H₂ or Fe. Once you balance everything else you can do the ones by themselves, it's much easier.
Hope this helps!
Answer:
c
Explanation:
hydrogen bonds are initially weak and collectively strong because they are partially positive ions