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AnnyKZ [126]
3 years ago
13

Draw the Lewis structure (including all lone pair electrons and any formal charges) for one of the four possible isomers of C3H9

N.
The isomer I am using is propylamine, CH3 (CH2)2 NH2. How do you draw the lewis structure? Please include lone pairs and formal charges if needed.

Chemistry
1 answer:
Alexus [3.1K]3 years ago
6 0

Answer and Explanation

The isomer picked is the N-Propylamine.

It has a lone pair of electron available on the electron rich Nitrogen and no formal charge.

Since it will be hard to draw the Lewis structure in this answer format, I'll attach a picture of the Lewis structure to this answer.

The lone pair of electron is shown by the two dots on the Nitrogen atom.

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A single hydrogen atom has a mass of 1.67 × 10−24 g. A sodium atom has an atomic mass of 23. How many sodium atoms are required
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<h3>Answer:</h3>

                      2.55 × 10²² Na Atoms

<h3>Solution:</h3>

Data Given:

                 M.Mass of Na  =   23 g.mol⁻¹

                 Mass of Na  =  973 mg  =  0.973 g

                 # of Na Atoms  =  ??

Step 1: Calculate Moles of Na as:

               Moles  =  Mass ÷ M.Mass

               Moles  =  0.973 g ÷ 23 g.mol⁻¹

               Moles  =  0.0423 mol

Step 2: Calculate No, of Na Atoms as:

As 1 mole of sodium atoms counts 6.022 × 10²³ and equals exactly to the mass of 23 g. So, we can write,

               Moles  =  No. of Na Atoms ÷ 6.022 × 10²³ Na Atoms.mol⁻¹

Solving for No. of Na Atoms,

               No. of Na Atoms  =   Moles × 6.022 × 10²³ Na Atoms.mol⁻¹

               No. of Na Atoms  =   0.0423 mol × 6.022 × 10²³ Na Atoms.mol⁻¹

               No. of Na Atoms  =  2.55 × 10²² Na Atoms

<h3>Conclusion: </h3>

                          2.55 × 10²² sodium atoms are required to reach a total mass of 973 mg in a substance of pure sodium.


5 0
4 years ago
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