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fredd [130]
3 years ago
14

When burning petrol in motor vehicles two gases form which contribute to acid rain. what are the two gases?

Chemistry
1 answer:
sukhopar [10]3 years ago
8 0
Nitrogen and Oxygen react to form Nitrogen Oxides. These gasses irritate the lungs and cause acid rain.
You might be interested in
If I want to accelerate a mass of 3 kg at 5 m/s2 then how much force should I apply?
Stolb23 [73]

<u>Answer:</u> The force that must be applied is 15 N.

<u>Explanation:</u>

Force exerted on the object is defined as the product of mass of the object and the acceleration of the object.

Mathematically,

F=m\times a

where,

F = force exerted = ?

m = mass of the object = 3 kg

a = acceleration of the object = 5m/s^2

Putting values in above equation, we get:

F=3kg\times 5m/s^2=15N

Hence, the force that must be applied is 15 N.

5 0
3 years ago
What is the mass of a sample of metal that is heated from 58.8°C to 88.9°C with a
Vadim26 [7]

Answer:

\boxed {\boxed {\sf 333 \ grams}}

Explanation:

We are asked to find the mass of a sample of metal. We are given temperatures, specific heat, and joules of heat, so we will use the following formula.

Q= mc \Delta T

The heat added is 4500.0 Joules. The mass of the sample is unknown. The specific heat is 0.4494 Joules per gram degree Celsius. The difference in temperature is found by subtracting the initial temperature from the final temperature.

  • ΔT= final temperature - initial temperature

The sample was heated <em>from </em> 58.8 degrees Celsius to 88.9 degrees Celsius.

  • ΔT= 88.9 °C - 58.8 °C = 30.1 °C

Now we know three variables:

  • Q= 4500.0 J
  • c= 0.4494 J/g°C
  • ΔT = 30.1 °C

Substitute these values into the formula.

4500.0 \ J = m (0.4494 \ J/g \textdegree C)(30.1 \textdegree C)

Multiply on the right side of the equation. The units of degrees Celsius cancel.

4500.0 \ J = m (13.52694 J/g)

We are solving for the mass, so we must isolate the variable m. It is being multiplied by 13.52694 Joules per gram. The inverse operation of multiplication is division, so we divide both sides by 13.52694 J/g

\frac {4500.0 \ J }{13.52694 J/g}= \frac{m (13.52694 J/g)}{13.52694 J/g}

The units of Joules cancel.

\frac {4500.0 \ J }{13.52694 J/g}= m

332.6694729 \ g =m

The original measurements have 5,4, and 3 significant figures. Our answer must have the least number or 3. For the number we found, that is the ones place. The 6 in the tenth place tells us to round the 2 up to a 3.

333 \ g \approx m

The mass of the sample of metal is approximately <u>333 grams.</u>

8 0
2 years ago
30 POINTS!!!<br> NEED ASAL
nata0808 [166]

Answer:

ITS THE LAST ONE AND THE SECOND ONE

Explanation:

4 0
3 years ago
Find the mass of 250.00 ml of benzene. The density of benzene is 0.8765 g/ml. (Please show how you got this answer)
Ivenika [448]

Density is Mass per Volume

so

0,8765 g/ml = Mass of Benzene / 250 ml

Mass of Benzene = 219,125 gram

so 250 ml of benzene is equal to 219,125 gram

4 0
3 years ago
Balance the equation
nikklg [1K]

2C2H5OH + 2Na ---- 2C2H5ONa + H2

6 0
3 years ago
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