Question

An advertisement claims that a particular automobile can "stop on a dime". What net force would actually be necessary to stop an automobile of mass 890 kg traveling initially at a speed of 48.0 km/h in a distance equal to the diameter of a dime, which is 1.8 cm ?

Answer 1

Answer:

F = 4399 KN

Explanation:

given,

mass of automobile = 890 kg

initial speed = 48 km/h

                     = 48 × 0.278 = 13.34 m/s

using equation of motion

v² = u² + 2 a × s

0 = 13.34² - 2 a ×0.018

$a = \dfrac{13.34^2}{0.036}$

a = 4943.21 m/s²

F   = m × a

F   = 890 × 4943.21

F   =  4399456.9 N

F = 4399 KN

hence, the  Net force is F = 4399 KN