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Answer:
Explanation:
Conceptual analysis
To solve this problem we apply Newton's second law:
The acceleration of an object is proportional to the force F acting on it and inversely proportional to its mass m.
a = F / m
Where,
F = m * a Formula (1)
F: Force in Newtons (N)
m: mass in kg
a: acceleration in m/(s^2)
a = v / t Formula (2)
v: speed in m/s
t: time in seconds (s)
Known information
We know the following data:
m = 1kg
v = 1 m/s
t = 1s
Development of the problem:
In the Formula (2):
In the Formula (1):
Answer:
The correct answer is - fight or flight response or reaction.
Explanation:
According to Cannon, the fight or flight reaction is a strong emotion experienced by a person especially people experiences associated with a perceived threat.
This reaction takes place in form of arousal in a perceived threat or stress conditions. It helps in maintaining the body environment in panic or stressed conditions.
Tuberculosis mrsa are some things that are contracted by saliva where spores in the air from an infected person
sneezing as well
Answer:
Explanation:
An inelastic collision is one where 2 masses collide and stick together, moving as a single mass after the collision occurs. When we talk about this type of momentum conservation, the momentum is conserved always, but the kinetic momentum is not (the velocity changes when they collide). Because there is direction involved here, we use vector addition. The picture before the collision has the truck at a mass of 3520 kg moving north at a velocity of 18.5. The truck's momentum, then, is 3520(18.5) = 65100 kgm/s; coming at this truck is a car of mass 1480 kg traveling east at an unknown velocity. The car's momentum, then, is 1480v. The resulting vector (found when you pick up the car vector and stick the initial end of it to the terminal end of the truck's momentum vector) forms the hypotenuse of a right triangle where one leg is 65100 kgm/s, and the other leg is 1480v. Since we already know the final velocity of the 2 masses after the collision, we can use that to find the final momentum, which will serve as the resultant momentum vector in our equation (we'll get there in a sec). The final momentum of this collision is
p = mv and
p = (3520 + 1480)(13.6) so
p = 68000. Final momentum. The equation for this is a take-off of Pythagorean's Theorem and the one used to find the final magnitude of a resultant vector when you first began your vector math in physics. The equation is
which, in words, is
the final momentum after the collision is equal to the square root of the truck's momentum squared plus the car's momentum squared. Filling in:
and
and
and
and
so
v = 13.3 m/s at 72.6°