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vivado [14]
3 years ago
13

Calcium oxide write this in a formula

Physics
1 answer:
kykrilka [37]3 years ago
4 0

The formula for calcium oxide is CaO.

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Which best describes how heat energy moves within a system?
Rzqust [24]
<span>Heat energy is transferred from warmer objects to cooler objects.

</span>
8 0
3 years ago
Read 2 more answers
Match the term to the correct description.
Misha Larkins [42]

1
The flow of electrons from negative to positive.

3
Materials that can easily carry electricity from place to place.

4
Materials that do conduct electricity, just not as well as conductors.

5
Materials that stop the flow of electricity.

2
An object that slows down the flow of electric current but still allows some electric current to move, resulting in some of the energy being converted to heat (thermal energy) or light energy in the process.
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3 years ago
THE RIGHT ANSWER WILL RECEIVE A BRAINLESS AND POINTS AND THANKS!!!
poizon [28]

Answer:

391.67Hz

Explanation:

The fundamental frequency formula in string is expressed as;

Fo = V/2L

V is the velocity of the wave = 329m/s

L is the length of the string = 42cm = 0.42m

Substitute

Fo = 329/2(0.42)

Fo = 329/0.84

Fo = 391.67Hertz

Hence the  fundamental frequency of a mandolin string is 391.67Hz

4 0
3 years ago
What is the definition for the word energy?​
Lena [83]
Kinetic, thermal and electrical. There is more then one form of energy
4 0
3 years ago
A skier leaves the horizontal end of a ramp with a velocity of 25.0 m/s and lands 70.0 m from the base of the ramp. How high is
Valentin [98]

Answer:

<em>The end of the ramp is 38.416 m high</em>

Explanation:

<u>Horizontal Motion </u>

When an object is thrown horizontally with an initial speed v and from a height h, it follows a curved path ruled by gravity.

The maximum horizontal distance traveled by the object can be calculated as follows:

\displaystyle d=v\cdot\sqrt{\frac  {2h}{g}}

If the maximum horizontal distance is known, we can solve the above equation for h:

\displaystyle h=\frac  {d^2g}{2v^2}

The skier initiates the horizontal motion at v=25 m/s and lands at a distance d=70 m from the base of the ramp. The height is now calculated:

\displaystyle h=\frac  {70^2\cdot 9.8}{2\cdot 25^2}

\displaystyle h=\frac  {4900\cdot 9.8}{2\cdot 625}

h= 38.416 m

The end of the ramp is 38.416 m high

8 0
3 years ago
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