3 years ago

Calcium oxide write this in a formula

Physics

1 answer:

kykrilka [37]3 years ago

4 0

The formula for calcium oxide is CaO.

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Plzzz help me fast i have absolutly no f-r-i-c-k-e-n idea what this is or how to do it

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P.E =mgh

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Explanation:

= 2000J

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A northbound train and a southbound train meet each other on parallel tracks heading in opposite directions. The northbound trai

SSSSS [86.1K]

Answer:

50mph,60mph

Explanation:

Let speed of southbound train=x mph

Speed of northbound train,y=x+16 mph

Distance between two trains after 1.5 hour,174 miles.

We have to find the speed of two trains.

Distance= $speed\times time$

Using the formula

$174=1.5x+1.5(x+16)$

$174=1.5(x+x+16)$

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Answer:

The unit for power is the Watt

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A student is trying to demonstrate static electricity, so they rub two identical balloons with a neutral rabbit fur to give them

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3 years ago

A tradesman sharpens a knife by pushing it with a constant force against the rim of a grindstone. The 30-cm-diameter stone is sp

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Answer:

a. 0.21 rad/s2

b. 2.205 N

Explanation:

We convert from rpm to rad/s knowing that each revolution has 2π radians and each minute is 60 seconds

200 rpm = 200 * 2π / 60 = 21 rad/s

180 rpm = 180 * 2π / 60 = 18.85 rad/s

r = d/2 = 30cm / 2 = 15 cm = 0.15 m

a)So if the angular speed decreases steadily (at a constant rate) from 21 rad/s to 18.85 rad/s within 10s then the angular acceleration is

$\alpha = \frac{\Delta \omega}{\Delta t} = \frac{21 - 18.85}{10} = 0.21 rad/s^2$

b) Assume the grind stone is a solid disk, its moment of inertia is

$I = mR^2/2$

Where m = 28 kg is the disk mass and R = 0.15 m is the radius of the disk.

$I = 28*0.15^2/2 = 0.315 kgm^2$

So the friction torque is

$T_f = I\alpha = 0.315*0.21 = 0.06615 Nm$

The friction force is

$F_f = T_f/R = 0.06615 / 0.15 = 0.441 N$

Since the friction coefficient is 0.2, we can calculate the normal force that is used to press the knife against the stone

$N = F_f/\mu = 0.441/0.2 = 2.205 N$

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3 years ago