What would you get if you split a bar magnet in the middle?

Calculate the average induced voltage between the tips of the wings of a Boeing 747 flying at 940 km/hr above East Lansing. The

ANTONII [103]

Answer:

option (b)

Explanation:

B = 0.7 x 10^-4 T

v = 940 km/h = 940 x 5 / 18 = 261.11 m /s

l = 60 m

Th emotional emf is given by

e = B v l

e = 0.7 x 10^-4 x 261.11 x 60 = 1.096 V

e = 1.1 V

5 0

3 years ago

Describe the difference between balanced forces and action/reaction forces

Alecsey [184]

Balanced forces<span> act on the same object and </span>Action-Reaction forces<span> act on different objects.</span>

5 0

3 years ago

Read 2 more answers

The speaker at the concert has the sound intensity level of 100 dB if we listen from the distance 5 m.How far from the speaker d

Mademuasel [1]

Answer:

$28.11m$ far from the speaker the intensity drops to 85 dB.

Explanation:

In the equation for the Decibel scale

$(1). \: \:\beta =10 log(\dfrac{I}{I_0})$

The ratio of the intensities can be written as

$\frac{I}{I_0} = \dfrac{\frac{P}{A} }{\frac{P}{A_0} }$

$\dfrac{I}{I_0} = \dfrac{A_0}{A}.$

And since

$A = 4\pi r^2$

and

$A_0 = 4 \pi r_0^2$ ,

$\dfrac{A_0}{A} = \dfrac{4 \pi r_0^2}{4 \pi r^2} = \dfrac{r_0^2}{r^2}$

meaning

$\dfrac{I}{I_0} = \dfrac{r_0^2}{r^2}.$

Putting this into equation (1), we get:

$\boxed{ (2).\: \: \beta = 10log(\dfrac{r_0^2}{r^2})}$

Now, if the intensity is 100 dB when the distance is 5 meters, we have:

$100dB=10 log(\dfrac{r_02}{(5m)^2})$

$10= log(\dfrac{r_0^2}{25})$

by taking both sides to the exponent:

$10^{10}= \dfrac{r_0^2}{25}$

$r^2 = 25 *10^{10}\\r = 5 *10^5$

Now equation (2) becomes

$\beta = 10log(\dfrac{25*10^{10}}{r^2})$

when the intensity level is 85 dB we have

$85 = 10log(\dfrac{25*10^{10}}{r^2})$

$8.5 = log(\dfrac{25*10^{10}}{r^2})$

take both sides to exponents and we get:

$10^{8.5} =10^{ log(\dfrac{25*10^{10}}{r^2})}$

$10^{8.5} =\dfrac{25*10^{10}}{r^2}$

$r^2 = \dfrac{25*10^{10}}{10^{8.5}}$

$\boxed{r = 28.11m}$

Thus, $28.11m$ far from the speaker the intensity drops to 85 dB.

7 0

3 years ago

The Sun delivers an average power of 1150 W/m2 to the top of the Earth’s atmosphere. The permeability of free space is 4π × 10−7

My name is Ann [436]

Answer:

E=930.84 N/C

Explanation:

Given that

I = 1150 W/m²

μ = 4Π x 10⁻⁷

C = 2.999 x 10⁸ m/s

E= C B

C=speed of light

B=Magnetic filed ,E=Electric filed

Power P = I A

A=Area=4πr² ,I=Intensity

$I=\dfrac{CB^2}{2\mu_0}$

$I=\dfrac{CE^2}{2\mu_0 C^2}$

$E=\sqrt{{2I\mu_0 C}}$

$E=\sqrt{{2\times 1150\times 4\pi \times 10^{-7}(2.99792\times 10^8)}}$

E=930.84 N/C

Therefore answer is 930.84 N/C

4 0

3 years ago

How does visible Light travel through outer space?

Dima020 [189]

By the electromagnetic "vibrations" that make up light. Said EM vibrations are an electric field and a magnetic field at right angles to each other and to the direction of propagation/travel. Light travels by the same "mechanism" that X rays travel, radio waves travel and anything else in the vast electromagnetic spectrum. Probably how I'm able to type these words on a computer key board and have them transmitted "Wi Fi" like, to you, the hapless recipient. You're a Cheetah ??? That means you can run like the wind ????

7 0

3 years ago