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Valentin [98]
3 years ago
5

Calculate the current through R2.

Physics
2 answers:
sertanlavr [38]3 years ago
7 0

Answer:

The total resistance is 15 Ω, the total current is 1A, The potential drop in R1 and R2 are 10V and 5V respectively and the total power develped is 15 W.

Explanation:

First it is necessary to simplify the circuit. We can do this by calculating the total or equivalent resistance Re. For series resistance arrangement, Re is computed as:

RT = R1 + R2 = 5 Ω + 10 Ω = 15 Ω

According to Ohm’s law the total current can be calculated dividing the total voltage V by Re:

I = V/Re = 15V/15Ω = 1A  

This current will be the same current through R1 and R2. Then we can compute the potential drop across R2 multiplying the current across R1 by the resistance:

VR1 = I*R2 = 1 A * 10 Ω = 10 V  

The potential drop across R2 is obtained in the same way as R1, considering R2 resistance:

VR2 = I*R1 = 1 A * 5Ω = 5 V

The total power could be calculated multiplying the total current I by the total voltage:

P = I*V = 1 A * 15 V = 15 W

alexira [117]3 years ago
5 0

Answer:

Explanation:

I posted the exact question and this is what someone sent me if u understand it let me know cuz i dont

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Answer:

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Explanation:

We need to find the speed of the rain in the "y" direction. We have:

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Hence, the speed of the car and the speed of the raindrop are related by:

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Therefore, the speed of the raindrop is 11.55 m/s.

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3 years ago
Homework 7 Adaptive Follow-Up Problem 25.68 Item 4 Constants A cylindrical copper cable 3.30 km long is connected across a 220.0
xenn [34]

Answer:

 0.446 mm  

0.066 V/m

Explanation:

Given  

We are given the length of the copper cable L = 3.30 km and the potential difference is V = 220 V  

Solution  

(a) We want to find the diameter d of the cable when the dissipated power is P = 50W. The power consumed by the cable depends on its resistance R and it is given by equation in the form

P= V^2/R                                                (1)

Where V is the voltage in the cable. Now let us solve equation (1) for R and plug our values for V and P into equation (1) to get R  

R = V^2/P = (220)^2/(50) = 968Ω

Now we can determine the diameter of the copper wire. The resistance R of the wires depends on the area of the wire, resistivity and the length of the cable. Where equation gives us the relationship between these variables in the form  

R = pL/π*r^2                             (solve for r)

r = √pL/πR                             (2)

Now we can plug our values for Rep and L into equation (2) to get the radius of the cable where p for copper equals 1.72 x 10-8 Ω m

r =√pL/πR                    

 = √1.72 x 10-8 *3300m/968

 = 0.234 mm

Therefore, the diameter is d= 2r = 2(0.234  mm) =  0.446 mm  

(b) To determine the electric field we can use the values for the potential difference across the cable and the length of the cable, where the electric field is inversely proportional to the length of the cable as next  

E =V/L

  =220/3300m

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Answer:

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