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3 years ago

Calculate the current through R2.

Physics

2 answers:

sertanlavr [38]3 years ago

7 0

Answer:

The total resistance is 15 Ω, the total current is 1A, The potential drop in R1 and R2 are 10V and 5V respectively and the total power develped is 15 W.

Explanation:

First it is necessary to simplify the circuit. We can do this by calculating the total or equivalent resistance Re. For series resistance arrangement, Re is computed as:

RT = R1 + R2 = 5 Ω + 10 Ω = 15 Ω

According to Ohm’s law the total current can be calculated dividing the total voltage V by Re:

I = V/Re = 15V/15Ω = 1A

This current will be the same current through R1 and R2. Then we can compute the potential drop across R2 multiplying the current across R1 by the resistance:

VR1 = I*R2 = 1 A * 10 Ω = 10 V

The potential drop across R2 is obtained in the same way as R1, considering R2 resistance:

VR2 = I*R1 = 1 A * 5Ω = 5 V

The total power could be calculated multiplying the total current I by the total voltage:

P = I*V = 1 A * 15 V = 15 W

alexira [117]3 years ago

5 0

Answer:

Explanation:

I posted the exact question and this is what someone sent me if u understand it let me know cuz i dont

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Answer:

Kinetic energy

Explanation:

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2 years ago

Bowling ball and a balloon are dropped from a 50 m tall building at the same time. IN AIR which object will hit the ground firs

HACTEHA [7]

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3 years ago

A hard-boiled egg of mass 46.0 gg moves on the end of a spring with force constant 25.6 N/mN/m . The egg is released from rest a

soldi70 [24.7K]

Answer:

0.022kg/s

Explanation:

We are given that

Mass of boiled egg=46 g= $\frac{46}{1000} kg=0.046 kg$

$1kg=1000 g$

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Initial displacement= $A_1=0.296 m$

Final displacement= $A_2=0.12 m$

Time=t=4.55 s

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We have to find the magnitude of damping constant b.

We know that the displacement of the oscillator under damping motion is given by

$x=Ae^{-\frac{b}{2m}t}cos(w't+\phi)$

For maximum displacement $cos(w't+\phi)=1$

Therefore , $x=A_2$

Substitute the values

$A_2=A_1e^{-\frac{-b}{2m}t}$

$e^{-\frac{b}{2m}t}=\frac{A_2}{A_1}$

$-\frac{b}{2m}t=ln\frac{A_2}{A_1}$

$lnx=y\implies x=e^y$

Substitute the values

$-\frac{b}{2\times 0.046}\times 4.55=ln\frac{0.12}{0.296}$

$\frac{2\times 0.046}{4.55b}=ln\frac{0.296}{0.12}$

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Irina18 [472]

Answer:

See bolded below.

Explanation:

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_______________________________________________________

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