All categories

2 years ago

State Newton's law of universal gravitation in words. Then do the same with one equation.

1 answer:

7 0

Then do the same with one equation. every body attracts every other body with a force that, for any two bodies, is directly proportional to the product of their masses and inversely proportional to the square of the distance separating them. ... If F = G((m1m2)/d and d is smaller, then the force of gravity.

You might be interested in

What are the factors affecting gravitational force?

oee [108]

Answer:
Distance between objects
Mass of objects
Force of gravitational field

6 0

3 years ago

Are we really real or are we all an allusion?Do you believe in past lives?How do you think you died in past life?

OLEGan [10]

Answer:

I don't even know

Explanation:

Shower thoughts

8 0

2 years ago

Read 2 more answers

Given a force of 100 N and an acceleration of 5 m/s2, what is the mass

UNO [17]

Answer:

20 kg

Explanation:

Mass equals force divided by acceleration, so divide 100 N by 5 m/s2 and you get your mass: 20 kg

6 0

2 years ago

Read 2 more answers

An object is released from rest at time t = 0 and falls through the air, which exerts a resistive force such that the accelerati

rosijanka [135]

Answer:

A) $\frac{g}{b}(1-e^{-bt})$

Explanation:

Since a = g - bv,

We can substitute a = dv/dt into the equation.

Then, the equation will be like dv/dt = g - bv.

So we got first order differential equation.

As known, v = 0 at t = 0, and v = g/b at t = ∞.

Since $\frac{dv}{dt}= g - bv = b( \frac{g}{b} - v)$ ⇒ $\frac{dv}{ \frac{g}{b} - v}= bdt$

So take the integral of both side.

$- ln (\frac{g}{b} - v) = bt + C$

Since for t=0, v = 0 ⇒ $C =- ln (\frac{g}{b})$

$v = \frac{g}{b} + e^{-bt-ln(\frac{g}{b})} = \frac{g}{b}- \frac{g}{b}e^{-bt} = \frac{g}{b}(1-e^{-bt})$

5 0

2 years ago

Sarah, who has a mass of 55 kg, is riding in a car at 20 m/s. She sees a cat crossing the street and slams on the brakes! Her se

avanturin [10]

Answer:

-2200 N

Explanation:

The change in momentum of Sarah is equal to the impulse, which is the product between the force exerted by the seatbelt on Sarah and the time during which the force is applied:

$\Delta p=I\\m \Delta v = F \Delta t$