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3 years ago

State Newton's law of universal gravitation in words. Then do the same with one equation.

1 answer:

7 0

Then do the same with one equation. every body attracts every other body with a force that, for any two bodies, is directly proportional to the product of their masses and inversely proportional to the square of the distance separating them. ... If F = G((m1m2)/d and d is smaller, then the force of gravity.

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What is the difference between a tide and a wave.please answer.

Sedbober [7]

Answer:Tides are formed because of the interaction of the gravitational forces between the Earth, the moon, and the sun. ... Tides are made by the rising and falling sea levels with the action of gravity while waves are formed when several factors relating to the wind and water interact with each other

3 0

3 years ago

Calculate the true mass (in vacuum) of a piece of aluminum whose apparent mass is 4.5000 kg when weighed in air. The density of

sasho [114]

Answer:

m = 4.5021 kg

Explanation:

given,

Apparent mass of aluminium = 4.5 kg

density of air = 1.29 kg/m³

density of aluminium = 2.7 x 10⁷ kg/m³

true mass of the aluminium = ?

Weight in Vacuum

W = m g

W = ρV g

Air buoyancy acting on aluminium

B = ρ₀V g

Volume is the same in both cases since the volume of the aluminum

displaces an equal amount of volume air.

Apparent weight:

ρV g − ρ₀V g = 4.5 g

ρV − ρ₀V = 4.5

$V = \dfrac{4.5}{\rho - \rho_0}$

m = ρV

$m = \dfrac{4.5\times \rho}{\rho - \rho_0}$

$m = \dfrac{4.5\times 2700}{2700 - 1.29}$

m = 4.5021 kg

4 0

3 years ago

A spherical mirror gives an image magnified 5 times at a distance 5 m. determine whether the mirror is convex or concave? How mu

irakobra [83]

Answer:

1. Concave mirror.

2. 4.17 m or 417 cm.

Explanation:

The following data were obtained from the question:

Object distance (u) = 5 m

Magnification (M) = 5

Focal length (f) =..?

1. Identification of the mirror.

To determine whether or not the mirror is concave or convex, we must first of all calculate the image distance.

This can be obtained as follow:

Object distance (u) = 5 m

Magnification (M) = 5

Image distance (v) =.?

Magnification (M) = image distance (v) /object distance (u).

M = v/u

5 = v/5

Cross multiply

v = 5 x 5

v = 25 m

Since the image distance obtained is positive, the mirror is said to be a concave mirror.

2. Determination of the focal length of the mirro.

This can be obtained as follow:

Object distance (u) = 5 m

Image distance (v) = 25 m

Focal length (f) =...?

1/f = 1/v + 1/u

1/f = 1/25 + 1/5

1/f = 0.04 + 0.2

1/f = 0.24

Cross multiply

f x 0.24 = 1

Divide both side by 0.24

f = 1/0.24

f = 4.17 m

Converting the focal length of cm, we have:

1 m = 100 cm

Therefore, 4.17 m = 4.17 x 100 = 417 cm

Therefore, the focal length of the mirror is 4.17 or 417 cm.

4 0

3 years ago

A sodium ion, Na+ , has a positive charge because it

goldenfox [79]

D. lost an electron

because they have free electron in the outermost shell which they will like to denote, in order to attain stable configuration

3 0

3 years ago

Sometimes waves interfere with one another. What type of interference occurs when the crests of one wave and the troughs of anot

olga55 [171]

Destructive interference :)

3 0

4 years ago

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