3 years ago

State Newton's law of universal gravitation in words. Then do the same with one equation.

1 answer:

7 0

Then do the same with one equation. every body attracts every other body with a force that, for any two bodies, is directly proportional to the product of their masses and inversely proportional to the square of the distance separating them. ... If F = G((m1m2)/d and d is smaller, then the force of gravity.

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Unit 12 Exam

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You increase the acceleration of the car.

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1. A 9000 kg van was stopped at a traffic light when it rear-ended with an 850 compact car moving to the east at a velocity of 5

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Answer:

1.785 m/s

Explanation:

The momentum can be calculated using the expression below

M1 *V1 + M2 * V2 = (M1+M2) V3

M1= mass of van=9000 kg

M2= mass of car= 850kg

V3= velocity of entangled car

V1= Velocity of the van= 0

V2= velocity of the car= 5 m/ s

Substitute the values

(900×0) + (500×5)=( 900+500)× V3

2500=1400 V3

V3=2500/1400

V3= 1.785 m/s

Hence, velocity of the entangled cars after collision is 1.785 m/s

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As a laudably skeptical physics student, you want to test Coulomb's law. For this purpose, you set up a measurement in which a p

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Answer:

Explanation:

charge, q = 1.6 x 10^-19 C

distance, r = 911 nm = 911 x 10^-9 m

The Coulomb's force is given by

$F=\frac{Kq_{1}q_{2}}{r^{2}}$

$F=\frac{9\times 10^{9}\times 1.6\times 10^{-19}\times 1.6\times 10^{-19}}{\left (911\times 10^{-9} \right )^2}$

F = 2.78 x 10^-16 N

The force between the electron and the proton is 2.78 x 10^-16 N.

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A traditional unit of length in Japan is the ken (1ken =1.97 m) . What are the ratios of (a) square kens to a square meters? and

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In the past, most children who went sledding in the winter snow in Verland used wooden sleds with runners and steering bars. Ten

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(E) it seems like the best option

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