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Anarel [89]
3 years ago
15

Write the acid-base equilibrium reaction between clo– and h2o. ignore phases.

Chemistry
2 answers:
Liono4ka [1.6K]3 years ago
7 0
Hello! As we know that CLO- is a weak base, and when reacted with water it forms HClO and equilibrium is attained without going to complete conversion.

Debora [2.8K]3 years ago
3 0

Acid-base equilibrium reaction between {\text{Cl}}{{\text{O}}^ - } and {{\text{H}}_{\text{2}}}{\text{O}} is as follows:

\boxed{{\text{Cl}}{{\text{O}}^ - } + {{\text{H}}_{\text{2}}}{\text{O}} \to {\text{HOCl}} + {\text{O}}{{\text{H}}^ - }}  

Further Explanation:

Equilibrium is the state at which concentration of reactants and products do not change with time and becomes constant. At this condition, the rate of forward reaction becomes equal to that of backward reaction.

Consider a general equilibrium reaction as follows:

{\text{A}} + {\text{B}} \rightleftharpoons {\text{X}} + {\text{Y}}  

Where,

A and B are reactants.

X and Y are products.

In this reaction, sign of equilibrium indicates that the rate of forward reaction is equal to the rate of backward reaction. In other words, formation of X and Y is balanced by the consumption of A and B.

{{\text{H}}_{\text{2}}}{\text{O}} isamphoteric in nature that indicates it can act as both acid and base. As an acid, it can donate hydrogen ions in solutions whereas it can accept hydrogen ions due to presence of lone pair on it and acts like a base. But {\mathbf{Cl}}{{\mathbf{O}}^{\mathbf{ - }}} is a weak base so {{\mathbf{H}}_{\mathbf{2}}}{\mathbf{O}} acts as an acid when reacted with {\text{Cl}}{{\text{O}}^ - }. {\text{Cl}}{{\text{O}}^ - } accepts hydrogen ions donated by   molecule to form HOCl and as a result, {\text{O}}{{\text{H}}^ - } is also formed.

Acid-base equilibrium reaction between {\text{Cl}}{{\text{O}}^ - } and {{\text{H}}_{\text{2}}}{\text{O}} is as follows:

{\text{Cl}}{{\text{O}}^ - } + {{\text{H}}_{\text{2}}}{\text{O}} \to {\text{HOCl}} + {\text{O}}{{\text{H}}^ - }  

Learn more:

  1. Calculation of equilibrium constant of pure water at 25°C: brainly.com/question/3467841
  2. Complete equation for the dissociation of  (aq): brainly.com/question/5425813

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Equilibrium

Keywords: equilibrium, reactants, products, A, B, X, Y, concentration, forward reaction, backward reaction, HOCl, OH-, H2O, ClO-.

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There is 541.6 grams of calcium carbonate produced from 5.11 moles

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Number of moles of sodium carbonate ( Na2CO3) = 5.11 moles

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