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Dafna11 [192]
2 years ago
14

Why was the measurement unit for metal content in Experiments 1 and 2 different? In Experiment 1:

Chemistry
1 answer:
olya-2409 [2.1K]2 years ago
8 0

To identify why a metal measurement was different in the experiments look for the variable that was different in the experiment and analyze how this change affected the results.

<h3>What is an experiment?</h3>

An experiment is a procedure that aims at probing or discovering something. For example, you can test if a plant grows faster/slower by using an experiment.

<h3>What causes different results in similar experiments?</h3>

The most common cause for this situation is that one of the factors or variables is slightly different. For example, if I add 50mL of water to a plant rather than 20mL of water every day this might cause different results.

Based on this, if the metal content was different you should analyze if any of the factors changed in this experiment and find out how this change affected the general results.

Note: This question is incomplete because there is limited information about the experiment; due to this, I answered it based on general knowledge.

Learn more about experiments in: brainly.com/question/13270830

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Which choice(s) correctly rank(s) the bonds in terms of increasing polarity?
Marina CMI [18]

Answer:

(II) only correctly rank the bonds in terms of increasing polarity.

Explanation:

Bond polarity is proportional to difference in electronegativity between bonded atoms.

Atoms    Electronegativity          Bond        Electronegativity difference

Cl                          3.0                       Cl-F                      1.0

Br                          2.8                       Br-Cl                     0.2

F                            4.0                       Cl-Cl                      0

H                            2.1                       H-C                       0.4

C                            2.5                       H-N                       0.9

N                             3.0                      H-O                       1.4

O                             3.5                      Br-F                       1.2

I                               2.7                      I-F                         1.3

Si                             1.9                      Cl-F                       1.0  

P                              2.2                      Si-Cl                      1.1

                                                          Si-P                        0.3

                                                          Si-C                        0.6

                                                           Si-F                        2.1

So, clearly, order of increasing polarity : O-H > N-H > C-H

So, (II) only correctly rank the bonds in terms of increasing polarity

4 0
3 years ago
Determine the pH of a solution of 0.00278 M of HClO4. Report the answer to two digits past the decimal.
aleksandrvk [35]

Answer:

The pH of a solution of 0.00278 M of HClO₄ is 2.56

Explanation:

pH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance and is calculated as:

pH= - log [H⁺]= - log [H₃O⁺]

On the other hand , a Strong Acid is that acid that in an aqueous solution dissociates completely. In other words, a strong acid completely dissociates into hydrogen ions and anions in solution.

HClO₄ is a strong acid, so in aqueous solution it will be  totally dissociated. Then, the concentration of protons is equal to the initial concentration of  acid and the pH will be calculated:

pH= - log 0.00278

pH= 2.56

<u><em>The pH of a solution of 0.00278 M of HClO₄ is 2.56</em></u>

8 0
3 years ago
I have a brick, dimensions 4 cm tall, 9 cm wide, and 25 cm long, with a mass of 1250 g. What is the density?
Likurg_2 [28]

Answer:

1.389

Explanation:

P = m / V

m = 1250

V = 4x9x25 = 900

1250/900 = 1.388889

7 0
3 years ago
Determine which is the control group and which is the experimental group in the following scenario ( Scientists are testing a ne
Daniel [21]

Answer:

The group given the sugar pills.

Explanation:

The control group is the ones given sugar pills because they did not get the experimental aspirin

3 0
2 years ago
Read 2 more answers
Use the data in the table above to calculate an approximate ΔH∘ in kilojoules for the synthesis of hydrazine from ammonia:
ankoles [38]
DeltaH formation = deltaH of broken bonds - deltaH of formed bonds

Broken bonds: tiple bond N-N and H-H bond
Formed bonds: N-H and N-N bonds

You also have to take note of the molar coefficients

deltaH formation = <span> [(N≡N) + 2 * (H-H)] - [4 * (N-H) + (N-N)] 
                           = (945 + 2*436) - (4*390 + 240)
                            = 17 kJ/mol

The answer is 17 kJ/mol.</span>
8 0
3 years ago
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