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Dafna11 [192]
2 years ago
14

Why was the measurement unit for metal content in Experiments 1 and 2 different? In Experiment 1:

Chemistry
1 answer:
olya-2409 [2.1K]2 years ago
8 0

To identify why a metal measurement was different in the experiments look for the variable that was different in the experiment and analyze how this change affected the results.

<h3>What is an experiment?</h3>

An experiment is a procedure that aims at probing or discovering something. For example, you can test if a plant grows faster/slower by using an experiment.

<h3>What causes different results in similar experiments?</h3>

The most common cause for this situation is that one of the factors or variables is slightly different. For example, if I add 50mL of water to a plant rather than 20mL of water every day this might cause different results.

Based on this, if the metal content was different you should analyze if any of the factors changed in this experiment and find out how this change affected the general results.

Note: This question is incomplete because there is limited information about the experiment; due to this, I answered it based on general knowledge.

Learn more about experiments in: brainly.com/question/13270830

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We have that every gas satisfies the fundamental gas equation, PV=nRT where P is the Pressure, V is the volume of the gas, n are the moles of the gas, R is a universal constant and T is the Temperature in Kelvin. We have that PV/T=nR and during our process, the moles of the gas do not change (no argon enters or escapes our sample). See attached.

6 0
3 years ago
What is the concentration (M) of CH3OH in a solution prepared by dissolving 34.4 g of CH3OH in sufficient water to give exactly
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Answer:

4.67M

Explanation:

The concentration of methanol (CH3OH) can be calculated using the following:

Molarity (M) = number of moles(n)/volume(v)

However, mole is not given. It can be obtained by using:

Mole = mass / molar mass

Where; mass = 34.4g

Molar mass (MM) of CH3OH is:

= 12 + 1(3) + 16 + 1

= 12 + 3 + 17

= 32g/mol

mole = 34.4/32

mole = 1.075mol

The volume needs to be converted to L by dividing by 1000

230mL = 230/1000

= 0.230L

Molarity = mol/volume

Molarity = 1.075/0.230

Molarity = 4.6739

Molarity = 4.67M

The concentration of CH3OH in solution is 4.67M

5 0
2 years ago
Consider the chemical reaction represented below. CH4 + 2O2 CO2 + 2H2O + Heat Which of the following statements about this react
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A. the reaction releases heat
6 0
3 years ago
Read 2 more answers
Uses of carbon dioxide.​
andrey2020 [161]

Answer:

hello can you follow me

Explanation:

used in fire extinction, blasting rubber, foaming rubber and plastic

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Chemical formula for 2 butyene is <br>​
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\text{C}_4\text{H}_6

Explanation:

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