Given that the reactants are the very consituents (elements) of the final compound, the enthalpy change of this reaction is the same heat of formation, Hf.
That means that the enthalpy chage for the reaction is -296.8 kj/mol
<span>It is classified as a homogeneous mixture because you cannot see any of the parts of the solution because they've been mixed perfectly.</span>
Answer:
7 gram of Na2SO4 should be required to prepare 0.5L of a 0.100 M solution.
Explanation:
First of all the molecular weight of Na2SO4 is 142.08 gram.Now we all know that if the molecular weight of a compound is dissolved in 1000ml or 1 litee of water then the strength of that solution becomes 1 M.
According to the given question we have to prepare 0.100 M solution
1000 ml of solution contain 142.08×0.1= 14.208 gram Na2SO4
1 ml of solution contain 14.208÷1000= 0.014 gram
0.5L or 500ml of solution contain 0.014×500= 7gram Na2SO4.
So it can be stated that 7 gram of Na2SO4 should be required to prepare 0.5L of a 0.100M solution.
In physics, net force<span> is the overall </span>force<span> acting on an object. In order to calculate the </span>net force<span>, the body is isolated and interactions with the environment or other constraints are represented as </span>forces<span> and torques in a free-body diagram.
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This helps increase variation in the offspring.