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r-ruslan [8.4K]
3 years ago
5

Formula for Tricarbon heptabromide.

Chemistry
1 answer:
DiKsa [7]3 years ago
7 0
I believe it would be Au^4Cl8
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Which statement is true regarding methane and ammonia?
sukhopar [10]
The options for given question are as follow,

1) Methane molecules show hydrogen bonding. 
<span>2) Ammonia molecules show hydrogen bonding. </span>
<span>3) Methane has stronger hydrogen bonding than ammonia. </span>
<span>4) Both the compounds do not show hydrogen bonding. </span>
<span>5) Both the compounds have strong hydrogen bonding.
</span>
Answer:
            Correct answer is Option-2 (Ammonia molecules show hydrogen bonding).

Explanation:
                   Hydrogen bond interactions are formed when a partial positive hydrogen atom attached to most electronegative atom of one molecule interacts with the partial negative most electronegative element of another molecule. So, in Ammonia hydrogen gets partial positive charge as nitrogen is highly electronegative. While the C-H bond in Methane is non-polar and fails to form hydrogen bond interactions.
6 0
4 years ago
Read 2 more answers
Please show me the easiest way to memorize the 1st 20 elements​
dybincka [34]

Answer:

MAKE flashcards

Explanation:

Study them then get some one to test you. it works for me

8 0
4 years ago
Scientists have observed that hurricanes are strongest over water, and that hurricanes lose momentum and become weak when they r
asambeis [7]

Answer:

Explanation:                                                                                        

4 0
3 years ago
A solution is made by dissolving 58.125 g of sample of an unknown, nonelectrolyte compound in water. The mass of the solution is
e-lub [12.9K]

Answer:

molecular weight (Mb) = 0.42 g/mol

Explanation:

mass sample (solute) (wb) = 58.125 g

mass sln = 750.0 g = mass solute + mass solvent

∴ solute (b) unknown nonelectrolyte compound

∴ solvent (a): water

⇒ mb = mol solute/Kg solvent (nb/wa)

boiling point:

  • ΔT = K*mb = 100.220°C ≅ 373.22 K

∴ K water = 1.86 K.Kg/mol

⇒ Mb = ? (molecular weight) (wb/nb)

⇒ mb = ΔT / K

⇒ mb = (373.22 K) / (1.86 K.Kg/mol)

⇒ mb = 200.656 mol/Kg

∴ mass solvent = 750.0 g - 58.125 g = 691.875 g = 0.692 Kg

moles solute:

⇒ nb = (200.656 mol/Kg)*(0.692 Kg) = 138.83 mol solute

molecular weight:

⇒ Mb = (58.125 g)/(138.83 mol) = 0.42 g/mol

8 0
3 years ago
What is the concentration in mol L-l of a 12% solution of tetrahydrate magnesium chloride (MgCl2)?
madreJ [45]

The concentration in mol L-l (M) = 0.717

<h3>Further explanation</h3>

Given

12% solution of tetrahydrate magnesium chloride (MgCl₂)

Required

The concentration

Solution

Tetrahydrate magnesium chloride (MgCl₂)⇒MgCl₂.4H₂O

MW = Ar Mg+2. Ar Cl+8. Ar H + 4. Ar O

MW=24.31 + 2 x 35.45 + 8 x 1.01 + 4 x 16

MW=24.31+70.9+8.08+64

MW=167.29 g/mol

12% solution = 12 % m/v = 12 g in 100 ml solution

For 1 L solution :

\tt \dfrac{1}{0.1}\times 12~g=120~g

The concentration in g/L = 120 g/L

Convert grams to moles :

\tt mol=\dfrac{120}{167.29}=0.717

3 0
3 years ago
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