Question

Factor completely 16a^3b^7 + 2a^6b^4 - 22a^4b^5

Answer 1

Answer:

$2a^3b^4(8b^3+a^3-11ab)$

Step-by-step explanation:

$as^3b^4(8b^3) +2a^6b^4-22a^4b^5\\2a^3b^4(8b^3)+2a^3b^4(a^3)-22a^4b^5\\2a^3b^4(8b^3)+2a^3b^4(a^3)+2a^3b^4(-11ab)\\2a^3b^4(8b^3+a^3)+2a^3b^4(-11ab)\\2a^3b^4(8b^3+a^3-11ab)$