3 years ago

Factor completely 16a^3b^7 + 2a^6b^4 - 22a^4b^5

Mathematics

1 answer:

Alina [70]3 years ago

4 0

Answer:

$2a^3b^4(8b^3+a^3-11ab)$

Step-by-step explanation:

$as^3b^4(8b^3) +2a^6b^4-22a^4b^5\\2a^3b^4(8b^3)+2a^3b^4(a^3)-22a^4b^5\\2a^3b^4(8b^3)+2a^3b^4(a^3)+2a^3b^4(-11ab)\\2a^3b^4(8b^3+a^3)+2a^3b^4(-11ab)\\2a^3b^4(8b^3+a^3-11ab)$

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