All categories

3 years ago

Why does the number 54,289.00 have seven significant figures and not five

Physics

2 answers:

nadya68 [22]3 years ago

4 0

The 2 spots after the decimal still counts toward the total the figures

Andreyy893 years ago

3 0

thought it was 5 at first too. the 00 past the decimal at significant because it's expressing it is exactly to that point. sort of confusing.
say you measured a pencil with a ruler, and say it was 5" long roughly. you can only scientifically put down that the pencil is 5 inches not 5.0000 because your ruler doesn't go that many decimal places. when something is absolute is the only time you can add .0000000000000000000000 to it and it still be correct. an example of something that is absolute is like you have 10 fingers, 10 is absolute because it's exact 10.0000000000000000=10 fingers it's not any more and not any less.
Those two zeros are included after the decimal so they aqre significant. The rule is all final zeros after the decimal are significant
Since there is a decimal point present, start with the leftmost nonzero didgit. Count that digit and every other digit to the right of it.

You might be interested in

Two 10-cm-diameter charged rings face each other, 21.0 cm apart. Both rings are charged to +40.0 nC. What is the electric field

Katyanochek1 [597]

Complete question:

Two 10-cm-diameter charged rings face each other, 21.0 cm apart. Both rings are charged to +40.0 nC. What is the electric field strength at the midpoint between the two rings ?

Answer:

The electric field strength at the mid-point between the two rings is zero.

Explanation:

Given;

diameter of each ring, d = 10 cm = 0.1 m

distance between the rings, r = 21.0 cm = 0.21 m

charge of each ring, q = 40 nC = 40 x 10⁻⁹ C

let the midpoint between the two rings = x

The electric field strength at the midpoint between the two rings is given as;

$E_{mid} = E_{right} +E_{left}\\\\E_{right} = \frac{KQ}{(x^2 + r^2)^\frac{2}{3} } \\\\E_{leftt} = -\ \frac{KQ}{(x^2 + r^2)^\frac{2}{3} }\\\\E_{mid} = \frac{KQ}{(x^2 + r^2)^\frac{2}{3} } - \frac{KQ}{(x^2 + r^2)^\frac{2}{3} } = 0$

Therefore, the electric field strength at the mid-point between the two rings is zero.

7 0

2 years ago

Evaluating alternative options and choosing one option among them is called the theory of bounded rationality.

VikaD [51]

It is false, bounded rationality is the idea that rationality is limited when individuals make decisions. ... Limitations include the difficulty of the problem requiring a decision, the cognitive capability of the mind, and the time available to make the decision.

But one thing, NEXT TIME TELL US THE QUESTION FIRST AND DON'T JUST LEAVE BLINDLY ASKING SOMETHING.

5 0

1 year ago

A solenoid with 435 turns has a length of 7.50 cm and a cross-sectional area of 3.50 ✕ 10−9 m2. Find the solenoid's inductance a

OLga [1]

Answer:

Solenoid's inductance is 1.11 × 10^-8H

The average emf around the solenoid is 1.3 × 10^-5V

Explanation: Please see the attachments below

4 0

3 years ago

PLEASE HELP!

Anna [14]

Answer:

Explanation:

At constant pressure , work done by gas = P x ΔV where P is pressure and ΔV is change in volume

ΔV = 9.2 - 5.6 = 3.6 L

3.6 L = 3.6 x 10⁻³ m³

ΔV = 3.6 x 10⁻³ m³

P = 3.7 x 10³ Pa

So work done

= 3.7 x 10³ x 3.6 x 10⁻³ J

= 13.32 J .

( c ) is the answer , because work is done by the gas so it will be positive.

5 0

3 years ago

Read 2 more answers

During each cycle, a refrigerator ejects 610 kJ of energy to a high-temperature reservoir, and takes in 505 kJ of energy from a

jenyasd209 [6]

Answer

A. the work done on the refrigerant in each cycle is 105kJ

B the coefficient of performance of the refrigerator is 4.8

Explanation

Given data

Work done at high temperature T2 Qh=610kJ

Work done at low temperature T1 Ql=505kJ

We know that the net work done by the refrigerator is expressed as

Wnet= Qh-Ql

=610-505

=105kJ

Also we know that the coefficient of performance is expressed as

COP= Ql/Wnet

COP= 505/105

= 4.8

8 0

2 years ago