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swat32
3 years ago
14

Why does the number 54,289.00 have seven significant figures and not five

Physics
2 answers:
nadya68 [22]3 years ago
4 0
The 2 spots after the decimal still counts toward the total  the figures 
Andreyy893 years ago
3 0

thought it was 5 at first too. the 00 past the decimal at significant because it's expressing it is exactly to that point. sort of confusing.
say you measured a pencil with a ruler, and say it was 5" long roughly. you can only scientifically put down that the pencil is 5 inches not 5.0000 because your ruler doesn't go that many decimal places. when something is absolute is the only time you can add .0000000000000000000000 to it and it still be correct. an example of something that is absolute is like you have 10 fingers, 10 is absolute because it's exact 10.0000000000000000=10 fingers it's not any more and not any less.
Those two zeros are included after the decimal so they aqre significant. The rule is all final zeros after the decimal are significant
Since there is a decimal point present, start with the leftmost nonzero didgit. Count that digit and every other digit to the right of it.
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Answer:

50m/s2^

Explanation:

We know , by newton's law of motion .

F=ma

a=f/m

a=25/0.5

a=50m/s2^

Therefore , the acceleration of a softball is  .

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3 years ago
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if the efficiency of an electric furnace is 96%, then 96% of the input energy is transformed into thermal energy. what is the ot
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It is wasted, most likely as light, in this case, or it is lost during the transport of electricity.
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3 years ago
A 1000kg car is rolling slowly across a level surface at 1 m/s heading twoards a group o fsmall innocent children. The doors are
Degger [83]

Answer:

The force required to push to stop the car is 288.67 N

Explanation:

Given that

Mass of the car, m = 1000 kg

Initial speed of the car, u = 1 m/s

The car and push on the hood at an angle of 30° below horizontal, \theta=30^{\circ}

Distance, d = 2 m

Let F is the force must you push to stop the car.

According work energy theorem theorem, the work done is equal to the change in kinetic energy as :

W=\dfrac{1}{2}m(v^2-u^2)F\times d=\dfrac{1}{2}m(v^2-u^2)

v = 0

Fd\ cos\theta=\dfrac{1}{2}m(u^2)      F=\dfrac{\dfrac{1}{2}m(u^2)}{d\ cos\theta}F=\dfrac{\dfrac{1}{2}\times 1000\times (1)^2}{2\ cos(30)}F = -288.67 N

The force required to push to stop the car is 288.67 N

3 0
2 years ago
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Fiesta28 [93]

Answer:

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7 0
2 years ago
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You and a friend each carry a 15 kg suitcase up two flights of stairs, walking at a constant speed. Take each suitcase to be the
AlekseyPX

Answer:

Both of you did the same work but you expended more power.

Explanation:              

<em>Work done</em> by an object is calculated by force applied multiplied by the distance.

  W=F*d

From the figure given below let us calculate force applied bith you and yopur friend.

Let us take the stairs in positive x direction,

Work done by you W₁ ,

The force applied Fₓ = F - mgsinθ =maₓ

here aₓ = 0, because both of you move with constant speed

F - mgsinθ = 0

F=  mgsinθ

The work done by you on the suitcase is

W = F L cos0°  ,    where L is he length of the staircase.

W = FL = mgsinθL ,  by substituting value of F

Work done by you is W₁ = mgLsinθ

Similarly work done by your friend is W₂ = mgLsinθ.

Because both of you carry suitcase of same weight and in staircase is in same angle the force applied is same .

Therefore <em>work done by both of you is same</em> . Both of you did equal work.

The power , is defined as amount of energy converted or transfered per second or rate at which work is done .

P =\frac{W}{t} =\frac{FL}{t}

Power spend by you P₁ = mgLsinθ/t

P₁ = 15*9.8*Lsinθ/30

P₁ = 4.9L sinθ  eqn 1

Power spend by your friend is P₂ = mgLsinθ/t

P₂ =15*9.8*Lsinθ/60

P₂ = 2.45Lsinθ    eqn 2

Dividing eqn 1 and eqn 2

P₁ = 2P₂

You have spend more power than your friend .

Hence Both of you did equal work but you spend more power.

7 0
3 years ago
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