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Eduardwww [97]
3 years ago
9

1. in a series circuit, as light bulbs are added, the voltage at the battery increases/decreasees/remains the same

Physics
1 answer:
artcher [175]3 years ago
5 0
In a series circuit, as light bulbs are added the voltage at the battery remains the same but the current at the battery decreases.
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You accidentally slide a glass of iced tea off a table that is 0.75 m tall. How
Marizza181 [45]

Answer:

B

Explanation:

s=  \frac{1}{2} gt ^{2}

s=0.75

g=10

3 0
3 years ago
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A motor exerts a force of 12,00N to lift an elevator 8.0m in 7.0secs what is the power produced by the motor?
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Answer:

1371.4watt

Explanation:

from power=energy/time

BUT energy=force times distance

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3 years ago
The process by which you group things based on their similarities is known as classifying.
dusya [7]
True. Classifying by similarities is the basis for biological classification.
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3 years ago
a 28.7 KG sled is pulled forward with a 63 net force across the ground with MK equals 0.169 what is the acceleration of the sled
abruzzese [7]

Answer:

0.54\ \text{m/s}^2

Explanation:

F = Force on the sled = 63 N

m = Mass of sled = 28.7 kg

\mu_k = Coefficient of kinetic friction = 0.169

g = Acceleration due to gravity = 9.81\ \text{m/s}^2

The force balance of the system is given by

F-\mu_k mg=ma\\\Rightarrow a=\dfrac{F-\mu_k mg}{m}\\\Rightarrow a=\dfrac{63-0.169\times 28.7\times 9.81}{28.7}\\\Rightarrow a=0.54\ \text{m/s}^2

The acceleration of the sled is 0.54\ \text{m/s}^2.

5 0
3 years ago
A 4.00 kg ball is swung in a circle on the edge of a 1.50 m rope. The time it takes for the ball to complete one rotation is 3.4
lorasvet [3.4K]

Answer:

The answer is below

Explanation:

The length of the rope is equal to the radius of the circle formed by the complete rotation of the rope. Therefore the radius = 1.50 m.

a) The distance covered by the rope when completing one rotation is the same as the perimeter of the circle. Hence:

Distance covered in one rotation = 2π * radius = 2π * 1.5 = 3π meters

The velocity of the ball = Distance / time = 3π meters / 3.4 seconds = 2.77  m/s

b) The initial velocity (u) is 0 m/s, the final velocity is 2.77 m/s during time (t) = 3.4 s. Hence acceleration (a):

v = u + at

2.77 = 3.4a

a = 0.82 m/s²

c) Force on ball = mass * acceleration = 4 * 0.82 = 3.28 N

8 0
3 years ago
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