Answer:
a) $520
b) $580
c) Interest amount is same each year
Step-by-step explanation:
Given - Georgie put $500 in her savings account, earning interest at a rate of 4% each year. She did not make any more deposits or withdrawals.
To find - a) How much money was in the account after one year?
b) How much money was in the account after 4 years?
c) Was the amount of money earned in interest the same or different each year?
Proof -
Here given that,
Principal amount = $500
rate of interest = 4% = 4/100 = 0.04
Now,
a)
Amount = P [ 1 + RT ]
= 500 [ 1 + 0.04(1)]
= 500 [ 1 + 0.04] = 520
⇒Amount = $520
b)
Amount = P [ 1 + RT ]
= 500 [ 1 + 0.04(4)]
= 500 [ 1 + 0.16] = 580
⇒Amount = $580
c)
In 2nd year,
Amount = P [ 1 + RT ]
= 500 [ 1 + 0.04(2)]
= 500 [ 1 + 0.08] = 540
⇒Amount = $540
Now,
Interest in 1st year = 520 - 500 = 20
Interest in 2nd year = 540 - 520 = 20
So,
The interest amount is same each year
Answer:
p=65. the value of p is the amount of pencils packs.
Step-by-step explanation:
1.99p=129.35
129.35/1.99=65
Hi there!
You can use distributive property to solve this equation.
These are the list of terms you have to multiply :
a × a² = a³
a × -ab = -a²b
a × b² = ab²
b × a² = a²b
b × -ab = -ab²
b × b² = b³
add all of those terms...
a³ - a²b + ab² +a²b -ab² + b³
simplify by adding like terms... (- a²b + a²b , ab² - ab²)
a³ + b³
Hope this helped!! :)
7y 4x and 2x they all are paired with a variable
