Answer:
Step-by-step explanation:
A. H0: accident are evenly distributed
H1: accident are not evenly distributed
B. The critical value is chi²(0.01,7) = 18.4753
C. The decision rule would be to reject h0 and accept h1 if the test statistic is higher than the critical value
D. Test statistic = summation (Oi-Ei)²/E
This gives 24.6 from the table.
E. Based on these calculations, test statistic is > than critical value
24.6> 18.4753
F. The inference is that accidents are not evenly distributed at 0.01 level of significance.
26/100 or simplified to 13/50
Answer:
CI=P*(1 + R/100)^18
A=(CI + P) = P(1+R/100)^18
13500/P=1(100+R/100)^18
A/P=(100+R/100)^18
A/P=(100+R/100)^18
A=13500$ as (750 * 18)
(13500)/P=(1 +1.15/100)18
(13500)/P=(1+1.15/100)18
13500=((1.0115)^18
P=R$10989.02
Step-by-step explanation:
CI=Compound Interest
A=Amount
P=Principal.
Recall the Maclaurin expansion for cos(x), valid for all real x :
Then replacing x with √5 x (I'm assuming you mean √5 times x, and not √(5x)) gives
The first 3 terms of the series are
and the general n-th term is as shown in the series.
In case you did mean cos(√(5x)), we would instead end up with
which amounts to replacing the x with √x in the expansion of cos(√5 x) :
