A plane is heading south with a velocity of 150 kilometers/hour. It experiences a tailwind with a velocity of 20 kilometers/hour
2 answers:
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Answer:
(a) Acceleration of positron is 6.03 x 10¹³ m/s²
(b) Speed of positron after 8.70 x 10⁻⁹ s is 5.24 x 10⁵ m/s
Explanation:
Given :
Constant electric field, E = 343 N/C
Mass of positron, m = 9.1 x 10⁻³¹ kg
Charge of positron, q = +e = 1.6 x 10⁻¹⁹ C
(a) Coulomb force on the positron is determine by the relation :
F = q x E ....(1)
But, force is also equals to product of mass and acceleration. So,
F = ma .....(2)
Here a is acceleration.
From equation (1) and (2).
m x a = q x E
Substitute the values of q, E and m in the above equation.
a = 6.03 x 10¹³ m/s²
(b) Initially, the positron is at rest, so its initial speed is zero.
The equation of motion for positron is :
v = u + at
Here v is final speed, u is initial speed and t is time.
Since, u is zero, so the equation becomes :
v = at
Substitute 8.70 x 10⁻⁹ s for t and 6.03 x 10¹³ m/s² for a in the above equation.
v = 6.03 x 10¹³ x 8.70 x 10⁻⁹ m/s
v = 5.24 x 10⁵ m/s
Answer:
Explanation:
velocity of wave in a tense wire is given by the expression
v is velocity . T is tension and m is mass per unit length .
for steel wire
m = π r² ρ where r is radius and ρ is density
= 3.14 x (5.3 x 10⁻⁴)²x7.75 x 10³
= 683.57 x 10⁻⁵ kg/m
v =
= 1.47 x 10² m /s
= 147 m /s
for iron wire
m = π r² ρ where r is radius and ρ is density
= 3.14 x (5.3 x 10⁻⁴)²x7.86 x 10³
= 693.27 x 10⁻⁵ kg/m
= 146 m /s
Time taken to move from one end to another
= 17.7 / 147 + 28.5 / 146
= .12 + .195
= .315 s .