The relative velocity of the athlete relative to the ground is 5.2 m/s
The given parameters;
constant velocity of the athlete, V = 5.2 m/s
let the velocity of the ground = Vg = 0
The relative velocity concept helps us to determine the velocity of a moving object relative to a stationary observer.
The athlete is the moving object in this question while the ground is stationary.
The relative velocity of the athlete relative to the ground is calculated as follows;

Thus, the relative velocity of the athlete relative to the ground is 5.2 m/s
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They're never the same ray.
We have that the time, to the nearest minute, when the water level is at 1.125 m for the second time after midnight is

From the Question we are told that
Maximum height 
Minimum height 
Time for next high tide will occur
Generally Average Height

Therefore determine Amplitude to be

Generally, the equation for Time is mathematically given by
At t=0

Where

Therefore

Hence the Time at
is



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