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svp [43]
3 years ago
6

Please help! Asap! :)

Chemistry
2 answers:
timama [110]3 years ago
4 0

The first one is true.

The second one is false.

Crazy boy [7]3 years ago
4 0
5. true (Energy cannot be created nor destroyed)
6. false (Potential energy does NOT increase over time)
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Which of the following will occur when a solution of Pb(NO3)2(aq) is mixed with a solution of KI(aq)?
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When a solution of Pb(NO3)2(aq) is mixed with a solution of KI(aq), a precipitate of PbI₂ will form; K⁺ and NO₃⁻ are spectator ions.

<u>Explanation:</u>

When an aqueous solution of lead nitrate (Pb(NO₃)₂ is mixed with aqueous solution of potassium iodide (KI), then there is a precipitate formation of lead iodide (PbI₂), and the potassium  (K⁺) ion and nitrate (NO₃⁻) ion acts as spectator ions that is ions do not involved in the reaction.

The reaction can be represented as,

Pb(NO₃)₂(aq) + 2 KI (aq) → PbI₂(s) + 2KNO₃(aq)

The ionic equation can be written as,

Pb²⁺(aq) + 2 NO₃⁻(aq) + 2 K⁺(aq) + 2 I⁻(aq) →  PbI₂(s) + 2K⁺(aq) + 2NO₃⁻(aq)

On both sides of the equation, we have K⁺ and NO₃⁻ ions, which gets cancelled, and these 2 ions are called as spectator ions.

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