Answer the question given in the photo below

What was the major weakness of Wegener's theory of continental drift

Alik [6]

Alfred Wegener proposed the continental drift theory in four reasons. One, he hypothesized that the continents were once a giant continent. Two, he observed that there are fossils found of the same kind in the different locations. Three, he found that the edge of opposing continents somehow fits if they are combined, almost like a puzzle. And four, there are glacial scars that are left behind by a larger glacial continent. His greatest weakness of Alfred Wegeners’ continental drift theory was he could not explain what kind of force that caused this continents to move far from each other.

6 0

3 years ago

Becker did an experiment. Separately, Tracy did the exact same experiment. Becker and Tracy found they each got very different r

maxonik [38]

Answer:

I don't know

Explanation:

Maybe they shouldn't copy each other

5 0

3 years ago

Read 2 more answers

In the laboratory a student combines 40.6 mL of a 0.113 M copper(II) sulfate solution with 26.4 mL of a 0.329 M copper(II) iodid

Arisa [49]

Answer : The final concentration of copper(II) ion is, 0.198 M

Explanation :

First we have to calculate the moles of $CuSO_4$ and $CuI_2$ .

$\text{Moles of }CuSO_4=\text{Concentration of }CuSO_4\times \text{Volume of solution}$

$\text{Moles of }CuSO_4=0.113mol/L\times 0.0406L=0.00459mol$

Moles of $CuSO_4$ = Moles of $Cu^{2+}$ = 0.00459 mol

and,

$\text{Moles of }CuI_2=\text{Concentration of }CuI_2\times \text{Volume of solution}$

$\text{Moles of }CuI_2=0.329mol/L\times 0.0264L=0.00869mol$

Moles of $CuI_2$ = Moles of $Cu^{2+}$ = 0.00869 mol

Now we have to calculate the total moles of copper(II) ion and total volume of solution.

Total moles copper(II) ion = 0.00459 mol + 0.00869 mol

Total moles copper(II) ion = 0.0133 mol

and,

Total volume of solution = 40.6 mL + 26.4 mL = 64.0 mL = 0.067 L (1 L = 1000 mL)

Now we have to calculate the final concentration of copper(II) ion.

$\text{Final concentration of copper(II) ion}=\frac{\text{Total moles}}{\text{Total volume}}$

$\text{Final concentration of copper(II) ion}=\frac{0.0133mol}{0.067L}=0.198mol/L=0.198M$

Thus, the final concentration of copper(II) ion is, 0.198 M

5 0

3 years ago

By default, your numerical entry is scored as correct if it is within 1% of the correct answer. A rule of thumb is always to ent

IrinaK [193]

1) Multiply the correct answer by 1% => 7.80009 * 1/100 = 0.0780009

2) Calculate minimum and maximum values:

a) Maximum: 7.80009 + 0.0780009 = 7.8780909

b) Minimum: 7.80009 - 0.0780009 = 7.7220891

3) Valid range: [7.7220891, 7.8780909]

4) Conclusion: 7.80, 7.730 and 7.80703 are inside the range and are inside the tolerance, while 7.6363, 7.6 and 7.76 are not.

6 0

3 years ago

Prepare a project report on various samples of

san4es73 [151]

<h2>Project Reports</h2>

<h3>A) Mixture</h3>

This refers to the material that is made when different substances mix up physically and causes a reaction.

You can make on the project of Mixture -

1) Alloys
2)Colloids
3) Suspension
4) Solution

<h3>B) Compound</h3>

This refers to the chemical bond that holds different atoms tightly

You can make on the project of Compound -

1)Water
2)Methane
3)Carbon Dioxide
4) Sulfuric Acid

<h3>C) Elements</h3>

Based on the fact that the atom is the smallest indivisible part of an element, elements like phosphorous cannot be further broken down.

You can make on the project of Elements -

1) Mercury
2) Iron
3) Copper
4)Carbon

Read more about mixtures and compounds here:

brainly.com/question/491220

#SPJ1

8 0

2 years ago