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NemiM [27]
3 years ago
15

How does the addition of salt to solid ice affect the melting transition from solid to liquid?

Chemistry
2 answers:
serious [3.7K]3 years ago
7 0

Answer:

Im sure the answer is c

Hope this helped have a good day :) please mark me the brainliest answer?

Vadim26 [7]3 years ago
4 0
<h2>Answer:</h2>

The water would need to <u>B. absorb less energy during the plateau in order to melt</u>.  

<h2>Explanation:</h2>

Salt when added to ice lowers the freezing point of the ice. So, if ice is added to the solid ice it doesn't let it to freeze rather the temperature of water may fall but it won't freeze.

For melting, it needs less energy after adding salt because salt itself absorbs the energy from the surroundings to help the phase transition of water from solid to liquid.

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All of the alkali earth metals, Group 2, have two valence electrons. Which of these would represent the oxidation number of the
juin [17]
Your answer should be C.) +2. "All the elements in Group 2 have two electrons in their valence shells, giving them an oxidation state of +2." 


Credits: https://chem.libretexts.org/Core/Inorganic_Chemistry/Descriptive_Chemistry/Elements_Organized_by_Blo...

Hopefully this has helped! :)
5 0
3 years ago
Identify the following elements based on their chemical symbols:
abruzzese [7]

Answer:C:Carbon

H:Hydrogen

O:Oxygen

Explanation:Every element is represented by a letter that is easy to tell which element it is so you don't have to get confused.

3 0
3 years ago
Use Boyle's Law to solve this problem: A gas has a volume of 10.0 L at a pressure of 4.0 atm. If the gas expands to 20.0 L, what
NARA [144]

Answer:

P₂ = 2 atm

Explanation:

Given data:

Initial volume = 10.0 L

Initial pressure = 4.0 atm

Final volume = 20.0 L

Final pressure = ?

Solution:

The given problem will be solved through the Boly's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

4.0 atm × 10.0 L = P₂ × 20.0 L

P₂ = 40.0  atm. L/ 20.0 L

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7 0
3 years ago
Two chemical samples were heated individually in a flame and both produced an identical orange flame. What conclusion can you dr
cestrela7 [59]

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6 0
4 years ago
A sample of hydrogen peroxide (H202) has 2.0 grams of hydrogen (H) and 32 grams of oxygen (O). What is the percent composition o
Leto [7]

Answer:

O = 94.117%

H = 5.882%

Explanation:

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OH 1-  17g/mol

H 1+ = 1g/mol

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2 Grams H

32 grams O

Percentage composition of  Hydrogen peroxide

O = 32/34 = 94.117%

H =    2/34 =   5.882%

3 0
4 years ago
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