Answer:
Acceleration of the object is 
.
Explanation:
It is given that, the position of the object is given by :
![r=[2\ m+(5\ m/s)t]i+[3\ m-(2\ m/s^2)t^2]j](https://tex.z-dn.net/?f=r%3D%5B2%5C%20m%2B%285%5C%20m%2Fs%29t%5Di%2B%5B3%5C%20m-%282%5C%20m%2Fs%5E2%29t%5E2%5Dj)
Velocity of the object, 
Acceleration of the object is given by :
![a=\dfrac{d^2}{dt^2}([2\ m+(5\ m/s)t]i+[3\ m-(2\ m/s^2)t^2]j)](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7Bd%5E2%7D%7Bdt%5E2%7D%28%5B2%5C%20m%2B%285%5C%20m%2Fs%29t%5Di%2B%5B3%5C%20m-%282%5C%20m%2Fs%5E2%29t%5E2%5Dj%29)
Using the property of differentiation, we get :
So, the magnitude of the acceleration of the object at time t = 2.00 s is . Hence, this is the required solution.
The x component of the force is 8.4N * cos(31°) = 7.2N (2 s.f.)
B) The velocity of a car reduced from 50 km/h to 35 km/h over one minute
Answer:
Doing work' is a way of transferring energy from one object to another, energy is transferred when a force moves through a distance.
Explanation: So more energy, more work done bc u transferred more energy to move the object and doing the work. and if you only use a little of energy, the work done also only a little.
Answer:
The answer is already given... it's 31.25 cm
