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3 years ago

What are 2 ways objects interact after a collision?

1 answer:

swat323 years ago

5 0

Mommentum is transferred but d object wit a lower Mommentum moves in d direction of the object with the higher Mommentum

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Which statement best describes the force of gravity

Finger [1]

Gravity<span> is measured by the acceleration that it gives to freely falling objects. At Earth's surface the acceleration of </span>gravity<span> is about 9.8 metres (32 feet) per second per second.</span>

4 0

3 years ago

The direction of the acceleration of an object on a(n) _______________________ path is toward the _______________________ of the

aleksandrvk [35]

Answer:

circular...center

Explanation:

Physics

8 0

3 years ago

The speed of light in a material is found to be 2.07 x 108 m/s. What is the most likely material from the options below if the s

Paraphin [41]

Answer:

1.3636

Explanation:

Write the expression for the refractive index.

n=c/v

c= speed of light in air

v= speed of light in material

=(3×10^8 m/s)/(2.2×10^8 m/s)

=1.3636

4 0

4 years ago

Read 2 more answers

If we heated the ball up and kept the ring room temperature, would the ball be able to fit through the ring? (1 point) Why or wh

Fed [463]

Answer:

no:

Explanation:

it would grow and no longer be able to fit through the loop due to the hot air expanding.

8 0

3 years ago

For a wire has a circular cross section with a radius of 1.23mm.

Mila [183]

Answer:

$5.731\times 10^{-5}\ m/s$

Decrease

Explanation:

I = Current = 3.7 A

e = Charge of electron = $1.6\times 10^{-19}\ C$

n = Conduction electron density in copper = $8.49\times 10^{28}\ electrons/m^3$

$v_d$ = Drift velocity of electrons

r = Radius = 1.23 mm

Current is given by

$I=neAv_d\\\Rightarrow v_d=\dfrac{I}{neA}\\\Rightarrow v_d=\dfrac{3.7}{8.49\times 10^{28}\times 1.6\times 10^{-19}\times \pi (1.23\times 10^{-3})^2}\\\Rightarrow v_d=5.731\times 10^{-5}\ m/s$

The drift speed of the electrons is $5.731\times 10^{-5}\ m/s$

$v_d=\dfrac{I}{neA}$

From the equation we can see the following

$v_d\propto \dfrac{1}{n}$

So, if the number of conduction electrons per atom is higher than that of copper the drift velocity will decrease.

5 0

3 years ago