All categories

2 years ago

Question 12 (10 points)

Physics

1 answer:

Leni [432]2 years ago

6 0

Answer:

d jjh hhv g 7655 ijv 77_* uyfgj 3&88 huih

You might be interested in

oscillating spring mass systems can be used to experimentally determine an unknown mass without using a mass balance. a student

12345 [234]

Answer:

Mass, m = 6.18 kg

Explanation:

Given the following data;

Frequency, F = 10 Hz

Spring constant, k = 250 N/m

We know that pie, π = 22/7

To find the mass, we would use the following formula;

F = 1/2π√(k/m)

Where;

F is the frequency of oscillation.

k is the spring constant.

m is the mass of the spring.

Substituting into the formula, we have;

10 = 1/2 * 22/7 * √250/m

10 = 22/14 * √250/m

Cross-multiplying, we have;

140 = 22 * √250/m

Dividing both sides by 22, we have;

140/22 = √250/m

6.36 = √250/m

Taking the square of both sides, we have;

6.36² = (√250/m)²

40.45 = 250/m

Cross-multiplying, we have;

40.45m = 250

Mass, m = 250/40.45

Mass, m = 6.18 kg

3 0

3 years ago

Two people push on a boulder to try to move it. The mass of the boulder is 825 kg. One person pushes north with a force of 64 N.

stira [4]

Answer:

0.09 m/s²

Explanation:

Acceleration: This can be defined as the rate of change of velocity.

The S.I unit of acceleration is m/s².

From the question, expression for acceleration is given as

F' = ma

Using Pythagoras Theory,

√(F₁²+F₂²) = ma................... Equation 1

Where F₁ = Force of the First person on the boulder, F₂ = Force of the Second person on the boulder, F' = resultant force acting on the boulder, m = mass of the boulder, a = acceleration of the boulder.

make a the subject of the equation

a = √(F₁²+F₂²) /m................ Equation 2

Given: m = 825 kg, F₁ = 64 N, F₂ = 38 N,

Substitute into equation 2

a = [√(64²+38²)]/825

a = {√(5540)}/825

a = 74.43/825

a = 0.09 m/s²

4 0

3 years ago

The most practical way to guard against allergic reactions in restaurants guests is to

lord [1]

Read the ingredients on the menu carefully and ask the waitress if theres any other ingredients you should know about

8 0

4 years ago

5. What is the force of gravity on a

zvonat [6]

Answer:

32.40 N

Explanation:

Acceleration due to gravity on the moon is 1.62 m/s².

W = mg

W = (20 kg) (1.62 m/s²)

W = 32.40 N

3 0

4 years ago

Consider a supersonic missile flying at Mach 2.5 at an altitude of 10 km. Assume that the angle of the shock wave from the nose

NNADVOKAT [17]

Answer:

The distance at which nose of the vehicle will the shock wave impinge upon the ground is approximately 23km

Explanation:

Let

u be Mach angle

M be Mach Number = 2.5

h be altitude = 10km

d be distance between nose of the vehicle with which the shock wave impinge upon the ground

Using;

Sin u = 1/M

u = arcSin (1/M)

u = arcSin (1/2.5) = 23.58°

Using angle at a point rule = 90°

90 - 23.58 = 66.42°

Tan A = opp/adj

Tan 66.42° = d/10

2.2911 * 10 = d

d = 22.911km ≈ 23km

6 0

3 years ago