Answer:
42.29 g of BrF₃.
Explanation:
Molar mass of OF2 = 16 + (2 * 19)
= 54 g/mol
Number of moles of OF₂ = mass / molar mass
= 25/54
= 0.46 mol.
Number of OF₂ molecules = number of moles * avogadros constant
= 0.46 * 6.022 x 10²³
= 2.8 x 10^23 molecules of OF2.
Since each OF₂ molecule has 2 Fluorine atoms,
Number of Fluorine atoms in 25.0 g of OF₂ = 2 x 2.8 x 10²³
= 5.576 x 10²³ atoms of Fluorine.
Since 1 BrF₃ molecule has 3 Fluorine atoms,
number of BrF₃ molecules = Number of Fluorine atoms / 3
= 5.576 x 10²³ / 3
= 1.8587 x 10²³ molecules of BrF₃.
Number of moles of BrF₃ = number of molecules of BrF₃ / Avogadros constant
= (1.8587 x 10²³) / (6.022 x 10²³ )
= 0.30865 moles of BrF₃.
Molar mass of BrF₃ = 80 + (19 * 3)
= 137 g/mol
mass of BrF₃ = number of moles * molar mass
= 0.30865 * 137
= 42.29 g of BrF₃.
It is known as its molar mass.
The least malleable would be potassium
Reaction type : Double-Replacement reactions
<h3>Further explanation</h3>
Given
Reaction
MgCl2 +
Li2CO3 →
MgCO3 +
LiCl
Required
Balanced equation
Reaction type
Solution
Balanced equation
Li2CO3 (s) + MgCl2 (aq) → MgCO3 (s) + 2 LiCl (aq)
Double-Replacement reactions. Happens if there is an ion exchange between two ion compounds in the reactant to form two new ion compounds in the product
To predict whether this reaction can occur or not is one of them, the precipitation reaction.
MgCO3 is a precipitation compound
A compound always contains its component elements in fixed ratio
