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Bezzdna [24]
3 years ago
12

How to convert liters into milileters

Chemistry
1 answer:
Nutka1998 [239]3 years ago
8 0
1 liter = 1,000 milliliters
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Cecil writes the equation for the reaction of hydrogen and oxygen below.
Wittaler [7]

Answer:

C) to show that atoms are conserved in chemical reactions

Explanation:

When writing a chemical reaction, we should always consider the Mass Conservation Law, which basically states that; in an isolated system; the total mass should remain constant, this is, the total mass of the reactives should be equal to the total mass of the products

For this case, we should add the apporpiate coefficients in order to be in compliance with this law:

2H₂ + O₂ → 2H₂O

So, we can check the above statement:

For reactives (left side):

4H

2O

For product (right side):

4H

2O

5 0
3 years ago
All organic molecules have what element in common
joja [24]

Every organic molecules/compound contains carbon (c).

Some other very abundant are hydrogen, nitrogen, oxygen, phosphorus, and sulfur.

I learned this with the acronym CHNOPS.

C - Carbon

H - Hydrogen

N - Nitrogen

O - Oxygen

P - Phosphorus

S - Sulfur

Hope this helps!


6 0
3 years ago
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Fusion reactors are more desirable than fission because:
Serga [27]
I believe it is A)fuel is more readily available:)
4 0
3 years ago
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How many atoms are equal to 1.5 moles of hellium
ANTONII [103]

Answer:

There are 1.8×1024 atoms in 1.5 mol HCl

Explanation:

6 0
2 years ago
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Combustion of hydrocarbons such as undecane (C_11H_24) produces carbon dioxide, a "greenhouse gas." Greenhouse gases in the Eart
bekas [8.4K]

Answer:

Volume of carbon dioxide is 428.23 L.

Explanation:

Below is the chemical reaction or chemical equation for the combustion of hydrocarbons such as undecane into carbon dioxide.

C_{11}H_{24}(l) + 17O_{2}(g) \to 11CO_{2} (g) + 12H_2O(g)

Here, undecane is in liquid form that reacts with gaseous oxygen (combustion)  and produces carbon dioxide and water as a product in the gaseous form.

The molar mass of undecane = 156.31 g/mol.

\text{Number of moles} = \frac{260g}{156.31g/mol} = 1.66 \ mol.

From the equation, it can be seen that 1 mole of undecane produces 11 moles of carbon dioxide. Therefore, 1.66 mol will produce 18.26 mol of carbon dioxide.

Now find the volume of 18.26 mol of carbon dioxide when the temperature is 13 degrees Celsius and pressure is 1 atm.

V = \frac{nRT}{P} \\

V = \frac{18.26 \times 0.082 \times 286 \ K}{1atm} \\

V = 428.23 \ L

6 0
3 years ago
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