Answer:
I don't see any of the following. If you could possibly tell me what the following answers are in the comments I can help :)
I’m sorry but where’s the worksheet lol......
<h3>
Answer:</h3>
= 19.712 kJoules
<h3>
Explanation:</h3>
- Heat of vaporization refers to the amount of heat required to change a unit mass of a substance from liquid to gaseous state without change in temperature.
To calculate the amount of heat, we use,
Amount of heat = Mass × Heat of vaporization
Q = m×Lv
Given;
Mass of liquid Zinc = 11.2 g
Lv of liquid Zinc = 1.76 kJ/g
Therefore;
Q = 11.2 g × 1.76 kJ/g
= 19.712 kJ
Thus, the amount of heat needed to boil 11.2 g of zinc is 19.712 kilo-joules.
Answer:
9.6 times 10 to 7th power divided by 3.0 times 10 to the 5th power can be written as follow. The final answer is 320.
Explanation:
When the divide 9.6 by 3.0 we get 3.2 and

So the calculation is as below.

Answer:
A pH scale reading 13 indicates a strong base.
Explanation:
From my understanding:
1 -4 is a strong acid
4 - 7 is weak acid
7 - 9 is a weak base
9 - 14 is a strong base