The order of the solutions from lowest to highest concentration : A, B, C
<h3>Further explanation</h3>
Given
the following solutions
Required
order of increasing concentration
Solution
Molarity shows the number of moles of solute in every 1 liter of solution.
Solution A : 0.5 moles : 2 L solution = 0.25 M
Solution B : 1 moles : 3 L solution = 0.33 M
Solution C : 1.5 moles : 4 L solution = 0.375 M
Noble gases belong to group 18 of the periodic table. These elements are inert because they have their valence orbital shells as ‘full’ hence do not participate in reactions since they cannot share electrons. These elements have a pattern in their electron configuration. Their outer most orbital shells has 8 electrons (with the exception of 2 for helium).
Density. water's density is always 1 g/ cm^3
Answer:
NA = 6.8 E-12 Kg H2(g) / hour
Explanation:
steady-state diffusion of A through non-diffuser B:
- NA = (DAB/RTz)(p*A1 - p*A2)
∴ (A): H2(g)
∴ (B): Pd
∴ DAB = 1.7 E-8 m²/s
∴ p*A1 = 2.0 Kg H2 / m³ Pd
∴ p*A2 = 0.4 Kg H2 / m³ Pd
∴ z = 6 mm = 6 E-3 m
∴ T = 600°C ≅ 873 K
∴ R = 8.314 J/mol.K = 8.314 N.m/mol.K
⇒ NA = ((1.7 E-8)/(8.314)(873)(6 E-3))(2.0 - 0.4)
⇒ NA = 6.246 E-10 mol/s.m³
for A = 0.25 m²
⇒ volume (v) = A×z = (0.25)(6 E-3) = 1.5 E-3 m³
∴ Mw H2(g) = 2.016 g/mol
⇒ NA = (6.246 E-10 mol/s.m³)(1.5 E-3 m³)(2.016 g/mol)(Kg/1000 g)(3600 s/h)
⇒ NA = 6.8 E-12 Kg H2(g)/h
