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Stells [14]
2 years ago
12

Help me please!!

Chemistry
1 answer:
WINSTONCH [101]2 years ago
3 0

Answer:

663 g

Explanation:

Step 1: Write the balanced equation

2 LiOH + CO₂ ⇒ H₂O + Li₂CO₃

Step 2: Calculate the moles corresponding to 825 L of CO₂

At standard pressure and temperature, 1 mole of CO₂ has a volume of 22.4 L.

825 L × 1 mol/22.4 L = 36.8 mol

Step 3: Calculate the moles of H₂O formed from 36.8 moles of CO₂

The molar ratio of CO₂ to H₂O is 1:1. The moles of H₂O formed are 1/1 × 36.8 mol = 36.8 mol.

Step 4: Calculate the mass corresponding to 36.8 moles of H₂O

The molar mass of H₂O is 18.02 g/mol.

36.8 mol × 18.02 g/mol = 663 g

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Answer:

Hydrogen

Explanation:

Hydrogen can never be central atom despite its low electronegativity

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Answer:

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3 years ago
Calculate the percentage of each element in acetic acid, hc2h3o2, and glucose, c6h12o6.
My name is Ann [436]
<em>Acetic acid, HC2H3O2</em>

First, calculate for the molar mass of acetic acid as shown below.
    M = 1 + 2(12) + 3(1) + 2(16) = 60 g

Then, calculating for the percentages of each element.
<em> Hydrogen:</em>
    P1 = ((4)(1)/60)(100%) = <em>6.67%</em>

<em> Carbon:</em>
   P2 = ((2)(12)/60)(100%) = <em>40%</em>

<em>Oxygen</em>
  P3 =((2)(16) / 60)(100%) = <em>53.33%</em>

<em>Glucose, C6H12O6</em>

The molar mass of glucose is as calculated below,
   6(12) + 12(1) + 6(16) = 180

The percentages of the elements are as follow,
 <em> Hydrogen:</em>
   P1 = (12/180)(100%) = <em>6.67%</em>

<em>Carbon:</em>
  P2 = ((6)(12) / 180)(100%) = <em>40%</em>

<em>Oxygen:</em>
  P3 = ((6)(16) / 180)(100%) = <em>53.33%</em>

b. Since the empirical formula of the given substances are just the same and can be written as CH2O then, the percentages of each element composing them will just be equal. 
6 0
3 years ago
Water is unique because the density of it's solid is less than the density of it's liquid. Describe how life would be different
Andreas93 [3]

Ice caps would float therefore providing insulation for aquatic life and ensuring they do not freeze due to the cool temperature.

6 0
3 years ago
When balancing redox reactions under basic conditions in aqueous solution, the first step is to:________.
natta225 [31]

Answer:

When balancing redox reactions under basic conditions in aqueous solution, the first step is to balance oxygen.

Explanation:

Oxidation-reduction reactions or redox reactions are those in which an electron transfer occurs between the reagents. An electron transfer implies that there is a change in the number of oxidation between the reagents and the products.

The gain of electrons is called reduction and the loss of electrons oxidation. That is to say, there is oxidation whenever an atom or group of atoms loses electrons (or increases its positive charges) and in the reduction an atom or group of atoms gains electrons, increasing its negative charges or decreasing the positive ones.

The oxidation and reduction half-reactions, in a basic medium, adjust the oxygens and hydrogens as follows:

In the member of the half-reaction that presents excess oxygen, you add as many water molecules as there are too many oxygen. Then, in the opposite member, the necessary hydroxyl ions are added to fully adjust the half-reaction. Normally, twice as many hydroxyl ions, OH-, are required as water molecules have previously been added.

In short, you first adjust the oxygens with OH-, then you adjust the H with H₂O, and finally you adjust the charge with e-

So, <u><em>when balancing redox reactions under basic conditions in aqueous solution, the first step is to balance oxygen.</em></u>

3 0
3 years ago
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