Answer:
663 g
Explanation:
Step 1: Write the balanced equation
2 LiOH + CO₂ ⇒ H₂O + Li₂CO₃
Step 2: Calculate the moles corresponding to 825 L of CO₂
At standard pressure and temperature, 1 mole of CO₂ has a volume of 22.4 L.
825 L × 1 mol/22.4 L = 36.8 mol
Step 3: Calculate the moles of H₂O formed from 36.8 moles of CO₂
The molar ratio of CO₂ to H₂O is 1:1. The moles of H₂O formed are 1/1 × 36.8 mol = 36.8 mol.
Step 4: Calculate the mass corresponding to 36.8 moles of H₂O
The molar mass of H₂O is 18.02 g/mol.
36.8 mol × 18.02 g/mol = 663 g
