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3 years ago

Oxygen, carbon dioxide, and other small molecules cross the plasma membrane through the process of ____.

Chemistry

1 answer:

lukranit [14]3 years ago

4 0

Answer: diffusion

Explanation:

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Compounds are ________ substances. A.)neutral B.)charged C.)ionized D.)non-neutral

son4ous [18]

Answer:

A.)neutral

because their ions have equal and opposite charges whose resultant charge is zero

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3 years ago

An example of a potassium compound containing both ionic and covalent bonds is?

gayaneshka [121]

It's a trick question because all of them contain both iconic and covalent bonds.

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4 years ago

12500 J/ (106 g) (4C) reduce to one

Sloan [31]

The given expression is $\frac{12500 J}{(106g)(4^{0}C )}$

This expression denotes the specific heat of a substance which indicates a heat energy of 12500 J is involved in raising the temperature of 106 g of the substance by $4^{0}C$ . Generally, the units of specific heat are $\frac{J}{g.^{0}C }$

$\frac{12500 J}{(106g)(4^{0}C )}$ = $\frac{12500 J}{(106g)(4^{0}C } = 29.5 \frac{J}{g^{0}C }$

Therefore, $\frac{12500 J}{(106g)(4^{0}C )}$ when reduced to one unit will be 29.5 $\frac{J}{g^{0}C }$

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3 years ago

Read 2 more answers

23.495 g sample of aqueous waste leaving a fertilizer manufacturer contains ammonia. The sample is diluted with 72.311 g of wate

Otrada [13]

Answer:

1.86% NH₃

Explanation:

The reaction that takes place is:

HCl(aq) + NH₃(aq) → NH₄Cl(aq)

We calculate the moles of HCl that reacted, using the volume used and the concentration:

32.27 mL ⇒ 32.27/1000 = 0.03227 L

0.1080 M * 0.03227 L = 3.4852x10⁻³ mol HCl

The moles of HCl are equal to the moles of NH₃, so now we calculate the mass of NH₃ that was titrated, using its molecular weight:

3.4852x10⁻³ mol NH₃ * 17 g/mol = 0.0592 g NH₃

The weight percent NH₃ in the aliquot (and thus in the diluted sample) is:

0.0592 / 12.949 * 100% = 0.4575%

Now we calculate the total mass of NH₃ in the diluted sample:

Diluted sample total mass = Aqueous waste Mass + Water mass = 23.495 + 72.311 = 95.806 g

0.4575% * 95.806 g = 0.4383 g NH₃

Finally we calculate the weight percent NH₃ in the original sample of aqueous waste:

0.4383 g NH₃ / 23.495 g * 100% = 1.86% NH₃

6 0

3 years ago

What volume is used to calculate the volume of a solid object

Degger [83]

Answer:

cubic measurements

Explanation:

i.e. cubic meter or cubic centimeter

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3 years ago

​ Oxygen, carbon dioxide, and other small molecules cross the plasma membrane through the process of ____.

Oxygen, carbon dioxide, and other small molecules cross the plasma membrane through the process of ____.