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3 years ago

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Which of the following elements has chemical properties similar to selenium? Which of the following elements has chemical proper

ties similar to selenium? sulfur fluorine nitrogen hydrogen

1 answer:

pashok25 [27]3 years ago

5 0

Answer:

Other chalcogens are oxygen, sulfur, tellurium, and polonium.

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1. Write the complete balanced equation for the following reaction:

artcher [175]

To completely balance the equation, we do elemental balance. First for C, the C in the left side is 5 so there must be 5 CO2. Balancing the H, H20 must be 9/2 to balance the left side. The total O on the right is 29/2. In the left side, O2 must be 27/4. Multiplying by 4 to get whole number stoich.coeff, we get 4 C5H9O + 27O2 = 20 CO2 + 18 H2O.

6 0

3 years ago

Some alkenes have geometric (cis-trans) isomers because ________. all of the carbon atoms in the compound are rigid and cannot r

faust18 [17]

Answer:

the carbon atoms in the double bond cannot rotate

Explanation:

Isomers refer to molecules that have a distinct arrangement of the atoms in the molecule but have the same molecular formula.

Alkenes refer to a series of unsaturated hydrocarbons that contain ethylene and propylene.

Some alkenes have geometric (cis-trans) isomers because <u>the carbon atoms in the double bond cannot rotate</u>.

7 0

2 years ago

A sample of O2 gas (2.0 mmol) effused through a pinhole in 5.0 s. It will take __________ s for the same amount of CO2 to effuse

ludmilkaskok [199]

Answer:

$\large \boxed{\text{5.9 s}}$

Explanation:

Graham’s Law applies to the effusion of gases:

The rate of effusion (r) of a gas is inversely proportional to the square root of its molar mass (M).

$r \propto \dfrac{1}{\sqrt{M}}$

If you have two gases, the ratio of their rates of effusion is

$\dfrac{r_{2}}{r_{1}} = \sqrt{\dfrac{M_{1}}{M_{2}}}$

The time for diffusion is inversely proportional to the rate.

$\dfrac{t_{2}}{t_{1}} = \sqrt{\dfrac{M_{2}}{M_{1}}}$

Let CO₂ be Gas 1 and O₂ be Gas 2

Data:

M₁ = 44.01

M₂ = 32.00

Calculation

$\begin{array}{rcl}\dfrac{t_{2}}{t_{1}} & = & \sqrt{\dfrac{M_{2}}{M_{1}}}\\\\\dfrac{t_{2}}{\text{5 s}}& = & \sqrt{\dfrac{44.01}{32.00}}\\\\& = & \sqrt{1.375}\\t_{2}& = & \text{5 s}\times 1.173\\& = & \mathbf{5.9 s} \\\end{array}\\\text{It will take $\large \boxed{\textbf{5.9 s}}$ for the carbon dioxide to effuse.}$

4 0

3 years ago

for the reaction shown compute the theoretical yield of product in moles each of the initial quantities of reactants. 2 Mn(s)+3

Y_Kistochka [10]

Answer:

2 mole MnO₂

Explanation:

2Mn(s) + 2O₂(g) => 2MnO₂(s)

4 0

3 years ago

Read 2 more answers

Consider the cell pt | h2 (1 atm); h+ (? m) || hg2cl2(s); cl− (1 m) | hg 2 h+ + 2 e − → h2 e 0 = 0.00 v hg2cl2 + 2 e − → 2 hg +

Dmitry [639]

Answer:

1.39

Explanation:

[Hg2Cl2]= 1M

[H^+] = ????

E°cell= 0.35V

E= 0.268 V

Therefore E for the reaction must -0.082 V

n= 2 moles of electrons

From Nernst Equation:

E= E°cell- 0.0592/n log [Red]/[Ox]

0.0268= 0.35- 0.0592/2 log 1/[Ox]^2

-0.082= -0.0296 log 1/[Ox]^2

log 1/[Ox]^2= 0.082/0.0296

log 1/[Ox]^2= 2.77

1/[Ox]^2=Antilog (2.77)

[Ox]^2=1.698×10^-3

[Ox] = 0.0412 M

But pH= -log [H^+]= -log(0.0412)= 1.385

3 0

3 years ago

Read 2 more answers