5 g of potassium oxalate react to produce 0.03 moles of calcium oxalate.
Calcium oxalate (CaC₂O₄) is obtained by the reaction of 5 g of potassium oxalate (K₂C₂O₄).
We can calculate the moles of CaC₂O₄ obtained considering the following relationships.
- The molar mass of K₂C₂O₄ is 184.24 g/mol.
- The mole ratio of K₂C₂O₄ to CaC₂O₄ is 2:1.
5 g of potassium oxalate react to produce 0.03 moles of calcium oxalate.
Learn more: brainly.com/question/15288923
I believe it is C, but I can't guarantee it.
Answer:
The answer to your question is the letter C. three times as much
Explanation:
Data
First step = 6 m
Second step = 18 m
Potential energy is the energy stored that depends on its position.
Formula
Pe = mgh
m = mass; g = gravity; h = height
Potential energy of the first step
Pe1 = 6mg
Potential energy of the second step
Pe2 = 18mg
-Divide the Pe2 by the Pe1
Pe2/Pe1 = 18mg/6mg
= 3
Answer:
I think the answer would be sodium
