Answer:
D) The equilibrium lies far to the left
Explanation:
According to the law of mass action, the equilibrium constant K for the reaction at 373K can be calculated as follows:
K = ![\frac{[CO][Cl_{2}]}{[COCl_{2}]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BCO%5D%5BCl_%7B2%7D%5D%7D%7B%5BCOCl_%7B2%7D%5D%7D)
= 2.19×10^{-10}
([X] means = concentration of X)
This means that in the equilibrium the concentration of the reactant (that is in the denominator) will be much higher (around 10^{10} fold) than the concentrations of the products (that are in the numerator), and this means that the equilibrium lies far to the left (to the reactants side) as very small amount of product is being formed.
Answer: True
It is true that entropy is greater at higher trophic levels compared to the lower levels. The amount of energy and entropy in a certain food chain varies between trophic level. It specifically increases from one trophic level to another.
Answer:
As you move across a period, the atomic mass increases because the atomic number also increases. ... The atomic mass for any given atom mainly comes from the mass of the protons and neutrons.
Explanation:
<span>3 elements
Nitrogen
Hydrogen
Oxygen
2 nitrogen 4 hydrogen and 3 oxygens
there are only 3 different elements</span>
Answer:- 14.0 moles of hydrogen present in 2.00 moles of ![[tex]C_6H_7N](https://tex.z-dn.net/?f=%20%5Btex%5DC_6H_7N)
.
Solution:- We have been given with 2.00 moles of 
and asked to calculate the grams of hydrogen present in it. It's a two step conversion problem. In first step we convert the moles of the compound to moles of hydrogen as one mol of the compound contains 7 moles of hydrogen. In next step the moles are converted to grams on multiplying the moles by atomic mass of H. The calculations are shown as:
= 14.0 g H
So, there are 14.0 g of hydrogen in 2.00 moles of .
