∠ ABD = 5(2X+1)
∠ DBC = 3X+6
∠ EBC = Y +135/2
∠ ABD and ∠ DBC are linear pairs
∴ ∠ ABD +∠ DBC = 180
∴ 5(2X+1) + 3X+6 =180
solve for x
∴ x = 13
∴∠ ABD = 5(2X+1) = 5(2*13+1) = 135
∠ DBC = 3x+6 = 3*13+6 = 45
∠ ABD and ∠ EBC are vertical angles
∴ ∠ ABD = ∠ EBC = 135
∴ y +135/2 = 135
∴ y = 135/2
The <span>statements that are true:
--------------------------------------</span><span>
C.) x=13
E.)measure of angle EBC =135
F.) angle DBC and angle EBC are linear pairs
</span>
Answer:
P = 49°
R = 131°
Q = 114°
S = 66°
Step-by-step explanation:
in a quadrilateral inscribed in a circle, the opposite angles are always supplementary, meaning they add up to 150
we are given opposite angles P and R (S is not given so we can't use Q and S)
P+R = 180
5y+14 + 15y + 26 = 180
20y + 40 = 180
20y = 140
y = 7
so...
P = 5(7) + 14 = 35 + 14 = 49
R = 180-49 (since opposite angles in inscribed quadrilaterals are supplementary) = 131
Q = (7)^2 + 65 = 49 + 65 = 114
S = 180-114 = 66
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