B:
Crossing the Y axis (y-intercept) means that the X value is zero. So, plug zero into the equation.
Y = 3(0)+1
Y =1
So the ordered pair for the Y intercept is (0,1)
For the X intercept, the Y value is equal to zero, so do the same thing except with Y
0 = 3(x) +1
-1 = 3x
x=-1/3
So the ordered pair is (-1/3,0)
E
Y intercept: (0,0)
X intercept (0,0)
the first x < 3 so x could be from - 1 till 3 in this graph
the other x > - 7 so x could be from from - 7 till - 3 in this graph
The ship sails at 20 km / h.
So
20 km / h x 2 h = 40 km
The boat moves 40 km to the northeast.
Then, in the same way:
20 km / h x 1 h = 20 km.
The ship moves 20 km northwest.
We solve this problem using vectors. In this case, we must perform the sum of two vectors a and b
a) magnitude = 40 km and direction 20 degrees east
b) magnitude = 20 km and direction 10 degrees northwest
In Cartesian coordinates, these vectors are written as:
a) 40sin (20º) i + 40cos (20º) j = 13,68i + 37,59j
b) -20sin (10th) i + 20cos (10th) j = -3,473i + 19,70j
The displacement vector of the ship would be the sum of a + b
a + b = 10,207i + 57,29j Finally, the magnitude of the a + b vector will tell us how far the ship is
√(10.21² + 57.29²) = 58.92km
(1/10) * 50 = 5
1/10 of 50 is 5
