Answer:
F = 0
Explanation:
Newton's second law is
F = ma
As in this case the two blocks move with constant speed, it implies that the acceleration is zero, therefore the force applied to the system is zero
F = 0
E = 0.5mv^2 = 0.5*44*10^2 = 2200J
The volume increases, but the surface area remains the same
6.
A. 1575 - 1265 = 310J
B. KE 1/2 MV^2
V=√2·KE/M = √2(310)/12 V = 7.2mls
C. PE = 1265 = mgh
h= 1265/mg = 1265/(12)(92) h= 10.8m
7.
A. KE = 1/2 mv^2 0.5(5)(12)^2 KE = 360J
B. PE = mgh = (5)(9.8)(2.6) PE = 127.4J
C. ME = KE + PE = 360 + 127.4 ME = 487.4J
