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Arlecino [84]
3 years ago
12

A rocket blasts off. In 10.0 seconds it is at 10,000 ft, traveling at 3600 mph. Assuming the direction is up, calculate the acce

leration. (Hint: the rocket is not under constant acceleration). 5280 ft/s2 528 ft/s2 100 ft/s2 200. ft/s2
Physics
2 answers:
marissa [1.9K]3 years ago
7 0

       Acceleration  =  (change in speed)  /  (time for the change)

Change in speed = (ending speed) - (beginning speed)

                            =     (3,600 mi/hr) - ( 0 )

                            =       3,600 mi/hr

                            =     same as  1 mile/second.

Acceleration  =  (1 mi/sec) / (10 sec)

                      =     0.1 mi/sec² .

But 1 mile = 5,280 ft,
so
                       0.1 mi/s²  =  528 ft/s²          
mojhsa [17]3 years ago
7 0

Answer:

 0.1 mi/s²  =  528 ft/s²    

Explanation:

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A transformer with X turns in primary coil and Y turns in secondary coil is used to change the magnitude of voltage to 240 V. Ca
Vinil7 [7]

The input voltage is 120 V and the transformer is a step up transformer due to increase in the voltage induced in the secondary coil.

<h3>Input voltage </h3>

The input voltage of the transformer is the voltage of the primary coil and it is calculated as follows;

Ns/Np = Es/Ep

where;

  • Ns is the number of turn in the secondary coil
  • Np is the number of turn in the primary coil
  • Es is the secondary voltage
  • Ep is the primary voltage

2X/X = 240/Ep

2 = 240/Ep

Ep = 240/2

Ep = 120 V

Thus, the transformer is a step up transformer due to increase in the voltage induced in the secondary coil.

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3 0
2 years ago
Please help. I don’t understand this
skad [1K]

The short answer is that the displacement is equal tothe area under the curve in the velocity-time graph. The region under the curve in the first 4.0 s is a triangle with height 10.0 m/s and length 4.0 s, so its area - and hence the displacement - is

1/2 • (10.0 m/s) • (4.0 s) = 20.00 m

Another way to derive this: since velocity is linear over the first 4.0 s, that means acceleration is constant. Recall that average velocity is defined as

<em>v</em> (ave) = ∆<em>x</em> / ∆<em>t</em>

and under constant acceleration,

<em>v</em> (ave) = (<em>v</em> (final) + <em>v</em> (initial)) / 2

According to the plot, with ∆<em>t</em> = 4.0 s, we have <em>v</em> (initial) = 0 and <em>v</em> (final) = 10.0 m/s, so

∆<em>x</em> / (4.0 s) = (10.0 m/s) / 2

∆<em>x</em> = ((4.0 s) • (10.0 m/s)) / 2

∆<em>x</em> = 20.00 m

5 0
3 years ago
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