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IrinaVladis [17]
3 years ago
13

What is 14 and 17/21 as a whole number???

Mathematics
2 answers:
ivann1987 [24]3 years ago
7 0

Answer:311/21

Step-by-step explanation:

Rashid [163]3 years ago
7 0

Answer:

311/21

the answer is 311/21

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Solve the system of linear equations below.
alexdok [17]

Answer:

The answer is X=3, Y=2

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3 years ago
Which set of lengths are not the side lengths of a right triangle? (A-28, 45, 53) (B-13, 84, 85) (C-36, 77, 85) (D-16, 61, 65) [
nikklg [1K]
Side lengths 16, 61, and 65 are not part of a right triangle.

A right triangle's sides should follow this formula, C being the largest number:

a^{2} + b ^{2} = c^{2}

16^{2} = 256

61^{2} = 3721

65^{2} = 4225

256 + 3721 = 3977

3977  \neq 4225
6 0
3 years ago
Which number sets (i.e. Natural, Whole, Integer, Rational, Real, etc.) are best suited to represent discrete functions? Why? Whi
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e

Step-by-step explanation:

4 0
3 years ago
f the centripetal and thus frictional force between the tires and the roadbed of a car moving in a circular path were reduced, w
LUCKY_DIMON [66]
The frictional force between the tires and the road prevent the car from skidding off the road due to centripetal force.

If the frictional force is less than the centripetal force, the car will skid when it navigates a circular path.

The diagram below shows that when the car travels at tangential velocity, v, on a circular path with radius, r, the centripetal acceleration of v²/ r acts toward the center of the circle.

The resultant centripetal force is (mv²)/r, which should be balanced by the frictional force of μmg, where μ =  coefficient of kinetic friction., and mg is the normal reaction on a car with mass, m.

This principle is applied on racing tracks, where the road is inclined away from the circle to give the car an extra restoring force  to overcome the centripetal force.
8 0
3 years ago
1+1=?<br> Sana Naman yung tamang sagot lang
Naily [24]

Answer:

2

Step-by-step explanation:

1+ 1 = 2

Hope this helps

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5 0
3 years ago
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