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siniylev [52]
3 years ago
5

Two students conduct a study to investigate the relationship between forearm length and height. Maria measures the subjects in c

entimeters. In a scatterplot of the data she sees a linear relationship between the variables, so she calculates the correlation coefficient. She determines that r = 0.86. John measures the same subjects in inches. He also calculates the correlation coefficient. What do you expect the correlation will be for John’s measurements?
Physics
1 answer:
inn [45]3 years ago
4 0

Answer:

r = 0.86

Explanation:

Correlation coefficients are the strength of the relationship between two variables.

Correlations can indicate anywhere between

  • 1 - for a strong positive relationship.
  • -1 - for a strong negative relationship.
  • 0 - for no relationship at all.

Looking at sample correlation coefficient formula which says

r_{xy} = S_{xy} ÷ (S_{x} × S_{y})

where S_{x} and S_{y} are the sample deviations and S_{xy} is the sample covariance, all of which will remain the same for Maria and John.

Hence, John's correlation will be approximately 0.86 since he would have approximately the same measurement as Maria's measurement when Maria's measurement is converted from centimeters to inches.

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What is the speed of a wave with a frequency of 6 Hz and a wavelength of 12 m? No links
myrzilka [38]

72 m/s

Explanation:

Given,

Frequency ( f ) = 6 Hz

Wavelength ( λ ) = 12 m

To find : -

Speed ( v ) = ?

Formula : -

v = f x λ

v

= 6 x 12

= 72 m/s

Therefore,

the speed of a wave with a frequency of 6 Hz and a wavelength of 12 m is 72 m/s.

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47) Which of the following types of energy is the kind that an object gains when it is raised to a higher point on a
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Answer:

kinetic

Explanation:

kinetic energy is powered by motion or gravity the steeper the hill is the faster a ball will roll

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There is a force which resists changes in motion, called
adoni [48]

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inertia 11

Explanation:

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Stars set about how many minutes earlier each day?<br><br> A. 8<br> B. 6<br> C. 4<br> D. 2
Furkat [3]
It is c which is four minutes per day
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3 years ago
Calculate the specific heat at constant volume of water vapor, assuming the nonlinear triatomic molecule has three translational
vampirchik [111]

Answer:

I) c=1385.667\frac{J}{kg K}

II)The difference from the value obtained on part I is: 2000-1385.67 =614.33 \frac{J}{Kg K}

The possible reason of this difference is that the vibrational motion can increase the value, since if we take in count this factor we will have a higher heat capacity, because molecules with vibrational motion require more heat to vibrate and necessary higher specific heat capacity.

Explanation:

From the problem we have the molar mass given M=18\frac{gr}{mol} of water vapor and at constant volume condition. It's important to say that the vapour molecules have 3 transitionsl and 3 rotational degrees of freedom and the rotational motion no contribution.

Part I

Calculate the specific heat at constant volume of water vapor, assuming the nonlinear triatomic molecule has three translational and three rotational degrees of freedom and that vibrational motion does not contribute. The molar mass of water is 18.0 g/mol=0.018kg/mol.

Let C_v (\frac{J}{Kg K}) the molar heat capacity at constant volume and this amount represent the quantity of heat absorbed by mole.

Let C (\frac{J}{Kg K}) the specific heat capcity this value represent the heat capacity aboserbed by mass.

For the problem we have a total of 6 degrees of freedom and from the thoery we know that for each degree of freedom the molar heat capacity at constant volume is given by C_v =\frac{R}{2} so the total for the 6 degrees of freedom would be:

C_v =6*\frac{R}{2}=3R=3x8.314\frac{J}{mol K}=24.942\frac{J}{mol K}

And by definition we know that the specific heat capacity is defined:

c=\frac{C_V}{M}

If we replace all the values we have:

c=\frac{24.942\frac{J}{mol K}}{0.018\frac{kg}{mol}}=1385.667\frac{J}{kg K}

So on this case the specific heat capacity with constant volume and with three translational and three rotational degrees of freedom is c=1385.667\frac{J}{kg K}

Part II

The actual specific heat of water vapor at low pressures is about 2000 J/(kg * K). Compare this with your calculation.

The difference from the value obtained on part I is: 2000-1385.67 =614.33 \frac{J}{Kg K}

The possible reason of this difference is that the vibrational motion can increase the value, since if we take in count this factor we will have a higher heat capacity, because molecules with vibrational motion require more heat to vibrate and necessary higher specific heat capacity.

4 0
3 years ago
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