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siniylev [52]
3 years ago
5

Two students conduct a study to investigate the relationship between forearm length and height. Maria measures the subjects in c

entimeters. In a scatterplot of the data she sees a linear relationship between the variables, so she calculates the correlation coefficient. She determines that r = 0.86. John measures the same subjects in inches. He also calculates the correlation coefficient. What do you expect the correlation will be for John’s measurements?
Physics
1 answer:
inn [45]3 years ago
4 0

Answer:

r = 0.86

Explanation:

Correlation coefficients are the strength of the relationship between two variables.

Correlations can indicate anywhere between

  • 1 - for a strong positive relationship.
  • -1 - for a strong negative relationship.
  • 0 - for no relationship at all.

Looking at sample correlation coefficient formula which says

r_{xy} = S_{xy} ÷ (S_{x} × S_{y})

where S_{x} and S_{y} are the sample deviations and S_{xy} is the sample covariance, all of which will remain the same for Maria and John.

Hence, John's correlation will be approximately 0.86 since he would have approximately the same measurement as Maria's measurement when Maria's measurement is converted from centimeters to inches.

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When light of wavelength 160 nm falls on a gold surface, electrons having a maximum kinetic energy of 2. 66 ev are emitted. Find
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When the light of wavelength is falling on gold surface, the electrons begin to exchange energies.

a)The work function in eV is Φ =5.097 eV.

b) The cut-off wavelength is λ₀ = 243.71 nm

c) The frequency is ν₀  =1.231 × 10¹⁵ Hz

<h3>What is work function?</h3>

The energy needed for a particle to escape and break through the surface.

The kinetic energy of the light emitted is 2.66 eV and wavelength of the light is 160 nm = 160 × 10⁻⁹ m.

a) The work function of the gold for given maximum kinetic energy is

Φ = hc / λ  - K.Emax

Substituting 6.626 × 10⁻³⁴ J.s for h, 3 × 10⁸ m/s for c and 2.66 eV for K.Emax, work function will be

Φ =8.16 × 10⁻¹⁹ J

1 eV = 1.6 × 10⁻¹⁹

The work function in eV is Φ =5.097 eV.

b) The cutoff wavelength is related to work function as

λ₀ = hc / Φ

Substitute the corresponding values into the equation, we get the cut off wavelength

λ₀ = 243.71 nm

c) The frequency corresponding to the cut-off wavelength is

ν₀ = c / λ₀

Substitute the corresponding values into the equation, we get the frequency,

ν₀  =1.231 × 10¹⁵ Hz

Therefore, the values for the following are

a)The work function in eV is Φ =5.097 eV.

b) The cut-off wavelength is λ₀ = 243.71 nm

c) The frequency is ν₀  =1.231 × 10¹⁵ Hz

Learn more about wave function.

brainly.com/question/17484291

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A person throws a baseball from height of 7 feet with an initial vertical velocity of 50 feet per second. Use the vertical motio
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