A more powerful engine means a plane will have a

A certain carbon monoxide molecule consists of a carbon atom mc = 12 u and an oxygen atom mo = 17 u that are separated by a dist

kvasek [131]

Answer:

a) x_{cm} = m₂/ (m₁ + m₂) d , b) x_{cm} = 52.97 pm

Explanation:

The expression for the center of mass is

$x_{cm}$ = 1 / M ∑ $x_{i}$ $m_{i}$

Where M is the total masses, mI and xi are the mass and position of each element of the system.

Let's fix our reference system on the oxygen atom and the molecule aligned on the x-axis, let's use index 1 for oxygen and index 2 for carbon

x_{cm} = 1 / (m₁ + m₂) (0+ m₂ x₂)

Let's reduce the magnitudes to the SI system

m₁ = 17 u = 17 1,661 10⁻²⁷ kg = 28,237 10⁻²⁷ kg

m₂ = 12 u = 12 1,661 10⁻²⁷ kg = 19,932 10⁻²⁷ kg

d = 128 pm = 128 10⁻¹² m

The equation for the center of mass is

x_{cm} = m₂/ (m₁ + m₂) d

b) let's calculate the value

x_{cm} = 19.932 10⁻²⁷ /(19.932+ 28.237) 10⁻²⁷ 128 10-12

x_{cm} = 52.97 10⁻¹² m

x_{cm} = 52.97 pm

7 0

3 years ago

a convex mirror has a focal length of 0.20 metre calculate the distance of the image of an object placed 0.30 cm from the mirror

anastassius [24]

8 because of the amount of calcium in the equator of the state Minnesota

4 0

3 years ago

On a spring scale that measures force, a reading shows the force of an object to be about halfway between 7 N and 8 N. Which of

Over [174]

Your answer is 7.5 N

3 0

3 years ago

Vector A has a magnitude of 16 m and makes an angle of 44° with the positive x axis. Vector B also has a magnitude of 13 m and i

marshall27 [118]

Answer with explanation:

The given vectors in are reduced to their componednt form as shown

For vector A it can be written as

$\overrightarrow{v}_{a}=16cos(44^{o})\widehat{i}+16sin(44^{o})\widehat{j}$

Similarly vector B can be written as

$\overrightarrow{v}_{b}=-13\widehat{i}$

Hence The sum and difference is calculated as

$\overrightarrow{v}_{a}+\overrightarrow{v}_{b}=16cos(44^{o})\widehat{i}+16sin(44^{o})\widehat{j}+(-13\widehat{i})\\\\\overrightarrow{v}_{a}+\overrightarrow{v}_{b}=(16cos(44^{o})-13)\widehat{i}+16sin(44^{o})\widehat{j}\\\\\therefore \overrightarrow{v}_{a}+\overrightarrow{v}_{b}=-1.49\widehat{i}+11.11\widehat{j}\\\\\therefore |\overrightarrow{v}_{a}+\overrightarrow{v}_{b}|=\sqrt{(-1.49)^{2}+11.11^{2}}=11.21m$

The direction is given by

$\theta =tan^{-1}\frac{r_{y}}{r_{x}}\\\\\theta =tan^{-1}\frac{11.11}{-1.49}=97.64^{o}$ with positive x axis.

Similarly

$\overrightarrow{v}_{a}-\overrightarrow{v}_{b}=16cos(44^{o})\widehat{i}+16sin(44^{o})\widehat{j}-(-13\widehat{i})\\\\\overrightarrow{v}_{a}-\overrightarrow{v}_{b}=(16cos(44^{o})+13)\widehat{i}+16sin(44^{o})\widehat{j}\\\\\therefore \overrightarrow{v}_{a}-\overrightarrow{v}_{b}=24.51\widehat{i}+11.11\widehat{j}\\\\\therefore |\overrightarrow{v}_{a}-\overrightarrow{v}_{b}|=\sqrt{(24.51)^{2}+11.11^{2}}=26.91m$

The direction is given by

$\theta =tan^{-1}\frac{r_{y}}{r_{x}}\\\\\theta =tan^{-1}\frac{11.11}{24.51}=24.38^{o}$ with positive x axis.

3 0

3 years ago

If a bowling ball weighing 3,630 g is accelerating down the alley at a rate of 4 m/s2 , then what is the net force applied to th

erastovalidia [21]

Answer:

<h3>The answer is 14.52 N</h3>

Explanation:

The force acting on an object can be found by using the formula

<h3>force = mass × acceleration</h3>

From the question

mass = 3630 g = 3.63 kg

acceleration = 4 m/s²

We have

force = 3.63 × 4

We have the final answer as

Hope this helps you

4 0

3 years ago