Question

A person throws a baseball from height of 7 feet with an initial vertical velocity of 50 feet per second. Use the vertical motion model, h = -16t2 + vt +s, where y is the initial velocity in feet per second and s is the height in feet, to calculate the amount of time the baseball is in the air before it hits the ground. Round your answer to the nearest tenth if necessary Time in air: _______ seconds​

Answer 1

Answer:

3.25 seconds

Explanation:

It is given that,

A person throws a baseball from height of 7 feet with an initial vertical velocity of 50 feet per second. The equation for his motion is as follows :

$h=-16t^2+vt+s$

Where

s is the height in feet

For the given condition, the equation becomes:

$h=-16t^2+50t+7$

When it hits the ground, h = 0

i.e.

$-16t^2+50t+7=0$

It is a quadratic equation, we find the value of t,

t = 3.25 seconds and t = -0.134 s

Neglecting negative value

Hence, for 3.25 seconds the baseball is in the air before it hits the ground.

Answer 2

Answer:

3.3

Explanation: