The power require to keep the car traveling is 6,666 W.
The power of the engine at the given efficiency is 3,999.6 W.
<h3>What is Instantaneous power?</h3>
This the product of force and velocity of the given object.
The power require to keep the car traveling is calculated as follows;
P = Fv
The power of the engine at the given efficiency is calculated as follows;
Learn more about efficiency here: brainly.com/question/15418098
Q: ken, 0.75 kg, moves toward a wall (his path normal to the wall) at 52 m/s. 13.0 ms after he touches the wall he pushes himself off in the opposite direction at 60 m/s. What is the magnitude of the average force the wall exerts on Ken during this rapid maneuver
Answer:
-6461.54 N
Explanation:
From Newton's Fundamental equation,
F = m(v-u)/t.................... Equation 1
Where F = Force exerted in sonic, m = mass of ken, v = final velocity, u = initial velocity, t = time.
Given: m = 0.75 kg, v = - 60 m/s (opposite direction), u = 52 m/s, t = 13 ms = 0.013 s
Substitute into equation 1
F = 0.75(-60-52)/0.013
F = 0.75(-112)/0.013
F = -84/0.013
F = -6461.54 N
Note: The negative sign tells that the force act in opposite direction to the initial motion of ken.
Hence the magnitude of the average force of the wall = -6461.54 N
Answer;
1 second
Explanation;
Two objects moving at the same speed will always stay the same distance apart. If two objects are moving at different speeds, the distance between them must change.
Therefore; if the distance will be the same and the speed is also the same then the time taken will be the same.
Answer:
The torque must be supplied by the motor to keep the wheel rotating at a constant angular velocity is 12 N-m.
Explanation:
Given that,
The coefficient of kinetic friction with the wheel is 0.60
Force acting against the wheel, F = 40 N
Let the distance is, r = 0.5 m
Torque is given by the product of force and distance. Here, the force will be :
Torque is given by :
So, the torque must be supplied by the motor to keep the wheel rotating at a constant angular velocity is 12 N-m.
This is the formula you need to memorize:
D = 1/2 · a · T²
Distance = (1/2) · (acceleration) · (Time²)
This formula tells the distance an object falls in any amount of time.
This question tells you the distance (58m), and you know the acceleration (gravity, 9.8 m/s²), so you can use this formula to find the time.
Distance = (1/2) · (acceleration) · (Time²)
58m = (1/2) · (9.8 m/s²) · (Time²)
Divide each side by (4.9 m/s²) : Time² = (58/4.9) seconds²
Take the square root of each side: <em>Time = 3.44 seconds </em>
