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3 years ago

7

diep buys a load of bread 65 centimeters long. for lunch every afternoon, he cuts 15 centimeters of bread for his sandwich. diep

wants to determine the length of the load of bread, i after d days. what is the equation of the scenario? is the graph of the equation continuous or discrete?

1 answer:

LiRa [457]3 years ago

6 0

Answer:

Continuous

Step-by-step explanation:

Its continous because after each day you take the same amount away and due to that it will be continous.

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Given the function f(x) = -2x2 + 4x - 7, find f(-4).<br> -55<br> -7<br> 25

Neko [114]

Answer:

f(-4)= -55

Step-by-step explanation:

We want to find f(x), or y, when x is equal to -4.

Therefore, we can substitute -4 in for x in the function.

f(x) = -2x^2 + 4x - 7

Substitute -4 in for x

f(-4) = -2(-4^2) + 4(-4) - 7

Evaluate the exponent

f(-4)=-2(16)+4(-4)-7

Multiply -2 and 16

f(-4)= -32+4(-4)-7

Multiply 4 and -4

f(-4)=-32-16-7

Subtract

f(-4)=-55

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2 years ago

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Find a power series for the function, centered at c, and determine the interval of convergence. f(x) = 9 3x + 2 , c = 6

san4es73 [151]

Answer:

$\frac{9}{3x + 2} = 1 - \frac{1}{3}(x - \frac{7}{3}) + \frac{1}{9}(x - \frac{7}{3})^2 - \frac{1}{27}(x - \frac{7}{3})^3 ........$

The interval of convergence is: $(-\frac{2}{3},\frac{16}{3})$

Step-by-step explanation:

Given

$f(x)= \frac{9}{3x+ 2}$

$c = 6$

The geometric series centered at c is of the form:

$\frac{a}{1 - (r - c)} = \sum\limits^{\infty}_{n=0}a(r - c)^n, |r - c| < 1.$

Where:

$a \to$ first term

$r - c \to$ common ratio

We have to write

$f(x)= \frac{9}{3x+ 2}$

In the following form:

$\frac{a}{1 - r}$

So, we have:

$f(x)= \frac{9}{3x+ 2}$

Rewrite as:

$f(x) = \frac{9}{3x - 18 + 18 +2}$

$f(x) = \frac{9}{3x - 18 + 20}$

Factorize

$f(x) = \frac{1}{\frac{1}{9}(3x + 2)}$

Open bracket

$f(x) = \frac{1}{\frac{1}{3}x + \frac{2}{9}}$

Rewrite as:

$f(x) = \frac{1}{1- 1 + \frac{1}{3}x + \frac{2}{9}}$

Collect like terms

$f(x) = \frac{1}{1 + \frac{1}{3}x + \frac{2}{9}- 1}$

Take LCM

$f(x) = \frac{1}{1 + \frac{1}{3}x + \frac{2-9}{9}}$

$f(x) = \frac{1}{1 + \frac{1}{3}x - \frac{7}{9}}$

So, we have:

$f(x) = \frac{1}{1 -(- \frac{1}{3}x + \frac{7}{9})}$

By comparison with: $\frac{a}{1 - r}$

$a = 1$

$r = -\frac{1}{3}x + \frac{7}{9}$

$r = -\frac{1}{3}(x - \frac{7}{3})$

At c = 6, we have:

$r = -\frac{1}{3}(x - \frac{7}{3}+6-6)$

Take LCM

$r = -\frac{1}{3}(x + \frac{-7+18}{3}+6-6)$

r = -\frac{1}{3}(x + \frac{11}{3}+6-6)

So, the power series becomes:

$\frac{9}{3x + 2} = \sum\limits^{\infty}_{n=0}ar^n$

Substitute 1 for a

$\frac{9}{3x + 2} = \sum\limits^{\infty}_{n=0}1*r^n$

$\frac{9}{3x + 2} = \sum\limits^{\infty}_{n=0}r^n$

Substitute the expression for r

$\frac{9}{3x + 2} = \sum\limits^{\infty}_{n=0}(-\frac{1}{3}(x - \frac{7}{3}))^n$

Expand

$\frac{9}{3x + 2} = \sum\limits^{\infty}_{n=0}[(-\frac{1}{3})^n* (x - \frac{7}{3})^n]$

Further expand:

$\frac{9}{3x + 2} = 1 - \frac{1}{3}(x - \frac{7}{3}) + \frac{1}{9}(x - \frac{7}{3})^2 - \frac{1}{27}(x - \frac{7}{3})^3 ................$

The power series converges when:

$\frac{1}{3}|x - \frac{7}{3}| < 1$

Multiply both sides by 3

$|x - \frac{7}{3}|$

Expand the absolute inequality

$-3 < x - \frac{7}{3}$

Solve for x

$\frac{7}{3} -3 < x$

Take LCM

$\frac{7-9}{3} < x$

$-\frac{2}{3} < x$

The interval of convergence is: $(-\frac{2}{3},\frac{16}{3})$

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2 years ago

Open-Ended Write an equation for the line in slope intercept form.

s344n2d4d5 [400]

Answer:

y = -2x+2

Writing the slope was the more difficult part. Writing the y-intercept was the easiest because I had to select to points on the line and solve to get the slope. The y-intercept was already explicitly shown on the line.

Step-by-step explanation:

y = mx+b

y = -2x + 2

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3 years ago

Look at the shaded shapes drawn on a square grid. The area of the rectangle A is double the area of square b is he correct?

Kaylis [27]

No it’s not double the area

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3 years ago

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-3x + y = 22<br> -12x – 10y=-10

dimaraw [331]

Answer:

<h3> x = -5, y = 7</h3>

Step-by-step explanation:

-3x + y = 22 ⇒ y = 3x + 22

-12x - 10y = -10 and y = 3x + 22

-12x - 10(3x + 22) = -10

-12x - 30x - 220 = -10

+220 +220

- 42x = 210

÷(-42) ÷(-42)

x = -5

y = 3(-5) + 22 = -15 + 22 = 7

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3 years ago