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iren2701 [21]
3 years ago
15

Which of Newton's laws of motion best illustrates the principle of inertia?

Physics
1 answer:
andrew-mc [135]3 years ago
5 0
Newton's first law of motion best illustrates the principle of inertia<span />
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The gravitational pull of the sun is greatest in our solar system because it...
Fudgin [204]

Answer:

B. has the greatest mass

Explanation:

mass & distance affect pull

grativy affects speed & shape of orbit of the planet

quiziz

5 0
3 years ago
ANSWER THE FOLLOWING QUESTION AND MAKE SURE TO GIVE A FULL DESCRIPTION TO HOW YOU GOT YOUR ANSWER (EX. make sure to use blank ru
vazorg [7]
Here is how I did it
6 0
4 years ago
The vertical displacement of the wave is measured from the ?
sergey [27]
The whole question is talking about the amplitude of a wave
that's transverse and wiggling vertically.

Equilibrium to the crest . . . that's the amplitude.

Crest to trough . . . that's double the amplitude.

Trough to trough . . . How did that get in here ?  Yes, that's
                               the wavelength, but it has nothing to do
                               with vertical displacement.

Frequency . . . that's how many complete waves pass a mark
                       on the ground every second.  Doesn't belong here.

Notice that this has to be a transverse wave.  If it's a longitudinal wave,
like sound or a slinky, then it may not have any displacement at all
across the direction it's moving.

It also has to be a vertically 'polarized' wave.  If it's wiggling across
the direction it's traveling BUT it's wiggling side-to-side, then it has
no vertical displacement.  It still has an amplitude, but the amplitude
is all horizontal.
6 0
3 years ago
A solid cylinder with a mass of 2.72 kg and a radius of 0.083 m starts from rest at a height of 4.20 m and rolls down a 88.7 ◦ s
Bingel [31]

Explanation:

According to the law of conservation of energy ,    

             Potential energy = kinetic energy

   mgh = \frac{1}{2} \times mv^{2} + \frac{1}{2} \times I \times \omega^{2}

                  I = \frac{mr^{2}}{2}

          \omega = \frac{v}{r}

     mgh = [\frac{1}{2} \times mv^{2}] + [\frac{1}{2} \times (\frac{mr^{2}}{2}) \frac{v^{2}}{r^{2}}]

     mgh = [\frac{1}{2} \times mv^{2}] + [\frac{1}{4} \times mv^{2}]

             g \times h = \frac{3}{4} \times v^{2}

             9.8 \times 4.2 = \frac{3}{4} \times v^{2}

                  v = 7.4 m/s

thus, we can conclude that the translational speed of the cylinder when it leaves the incline is 7.4 m/s.

5 0
3 years ago
Jenny and Betty are having a great time at Busch Gardens riding the Ubanga Banga bumper cars. Jenny, who is traveling southward
Alex777 [14]

Jenny is traveling southward.  In order to stop, she needs a northward acceleration.


A better way to say it:

Jenny is traveling southward in her bumper car, so the direction of her velocity is south.  In order to reduce her velocity to zero, a velocity of equal magnitude but directed north must be added to it.  Then the change in velocity is positive northward, and the change in velocity per unit time is acceleration.

6 0
3 years ago
Read 2 more answers
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