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2 years ago

Write some harms of friction.

Physics

2 answers:

Serjik [45]2 years ago

7 0

Answer:

Friction had many disadvantages and these are the har,s of friction too.

Explanation:

Disadvantages of friction are mainly forest fires, decreasing life expectancy of vehicles, damages many machines, generates heat, wear and tear, wastage of force/energy, etc. When two things in a forest rub against each other through an amount of force, friction will be present and it will cause a spark. This spark will be continued into a fire because of other materials like wood in the forest causing a forest fire. Secondly, vehicles work through moving many internal machines in them; this again includes friction and friction can damage the machines so to prevent it ppl grease the machines. decreasing life of vehicles is just a larger view of damaging the machines as this disadvantage of friction can be used anywhere. Wastage of force/ energy because when we roll a ball on a surface we have to put force on the ball to make it move forward but because friction moves in the opposite direction energy/force will be wasted there. Generating heat and wear & tear are some factors of friction which is also a harm.

Veseljchak [2.6K]2 years ago

3 0

Answer:

Friction produces unnecessary heat leading to the wastage of energy. The force of friction acts in the opposite direction of motion, so friction slows down the motion of moving objects. Forest fires are caused due to the friction between tree branches. However, friction can also cause problems in a car. Friction between moving engine parts increases their temperature and causes the parts to wear down. Friction can be both harmful and helpful, so it may be necessary to decrease or increase friction.

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2 years ago

A copper wire (density equal to 8900 kg / m3) 0.3 mm in diameter "floats" due to the force of the earth's magnetic field, which

Andrews [41]

Answer: $I=112.094\ A$

Explanation:

Given

density $\rho =8900\ kg/m^3$

diameter $d=0.3\ mm$

Magnetic field $B=5.5\times 10^{-5}\ T$

Force on the current carrying conductor placed in a magnetic field

$F=BIL\sin \theta$

where L=length of conductor

$\theta$ =angle between magnetic field and current

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Therefore

$\rho ALg=BIL\times \sin 90$

$8900\times \frac{\pi}{4}(0.3\times 10^{-3})^2L\times 9.8=5.5\times 10^{-5}\times I\times L$

$I=\frac{8900\times \pi\times 9\times 10^{-8}\times 9.8}{4\times 5.5\times 10^{-5}}$

$I=112.094\ A$

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2 years ago

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DedPeter [7]

I believe the answer is A.

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2 years ago

Read 2 more answers

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Ganezh [65]

Answer:

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Explanation:

https://en.wikipedia.org/wiki/Astronomical_unit

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3 years ago

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juin [17]

A perfectly elastic<span> collision is defined as one in which there is no loss of </span>kinetic energy<span> in the collision. Therefore, we just add the kinetic energies of each system. We calculate as follows:

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3 years ago