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3 years ago

Write some harms of friction.

Physics

2 answers:

Serjik [45]3 years ago

7 0

Answer:

Friction had many disadvantages and these are the har,s of friction too.

Explanation:

Disadvantages of friction are mainly forest fires, decreasing life expectancy of vehicles, damages many machines, generates heat, wear and tear, wastage of force/energy, etc. When two things in a forest rub against each other through an amount of force, friction will be present and it will cause a spark. This spark will be continued into a fire because of other materials like wood in the forest causing a forest fire. Secondly, vehicles work through moving many internal machines in them; this again includes friction and friction can damage the machines so to prevent it ppl grease the machines. decreasing life of vehicles is just a larger view of damaging the machines as this disadvantage of friction can be used anywhere. Wastage of force/ energy because when we roll a ball on a surface we have to put force on the ball to make it move forward but because friction moves in the opposite direction energy/force will be wasted there. Generating heat and wear & tear are some factors of friction which is also a harm.

Veseljchak [2.6K]3 years ago

3 0

Answer:

Friction produces unnecessary heat leading to the wastage of energy. The force of friction acts in the opposite direction of motion, so friction slows down the motion of moving objects. Forest fires are caused due to the friction between tree branches. However, friction can also cause problems in a car. Friction between moving engine parts increases their temperature and causes the parts to wear down. Friction can be both harmful and helpful, so it may be necessary to decrease or increase friction.

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The speed of light in air is 3.0 x 10^8 m/s. The speed of light in particular glass is 2.3 x 10^8 m/s. Use the information to de

olga_2 [115]

Answer:

33.61°

Explanation:

Refractive index is equal to velocity of the light 'c' in empty space divided by the velocity 'v' in the substance.

Or ,

n = c/v.

v is the velocity in the medium (2.3 × 10⁸ m/s)

c is the speed of light in air = 3.0 × 10⁸ m/s

So,

n = 3.0 × 10⁸ / 2.3 × 10⁸

n = 1.31

Using Snell's law as:

$n_i\times {sin\theta_i}={n_r}\times{sin\theta_r}$

Where,

${\theta_i}$ is the angle of incidence ( 25.0° )

${\theta_r}$ is the angle of refraction ( ? )

${n_r}$ is the refractive index of the refraction medium (air, n=1)

${n_i}$ is the refractive index of the incidence medium (glass, n=1.31)

Hence,

$1.31\times {sin25.0^0}={1}\times{sin\theta_r}$

Angle of refraction = $sin^{-1}0.5536$ = 33.61°

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3 years ago

Which describes a force acting on an object?

weeeeeb [17]

Answer:

Describing a Force:

To fully describe the force acting upon an object, you must describe both its magnitude and direction. Thus, 10 Newtons of force is not a complete description of the force acting on an object. 10 Newtons, downwards is a complete description of the force acting upon an object.

Explanation:

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3 years ago

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3 years ago

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Tju [1.3M]

Answer:

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Explanation:

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3 years ago

A 975-kg pickup comes to rest from a speed of 87.5 km/h in a distance of 125 m. Suppose the pickup is initially traveling in the

Savatey [412]

Answer:

A) Force = 2303.925 N in the negative x-direction

B) F ≈ 143998.28 N

C) Ratio = 62.5

Explanation:

A) Since the brakes are the only thing making the van to come to a stop, then first of all, we will calculate the force (in a component along the direction of motion of the car) that the brakes will apply on the van.

Let's find the deceleration using Newton's law of motion formula;

v² = u² + 2as

where;

v = final velocity,

u = initial velocity,

s = displacement

a = acceleration

We are given;

u = 87.5 km/h = 24.3056 m/s

s = 125 m

v = 0 m/s

Thus;

0 = (24.3056)² + 2a(125)

- (24.3056)²= 250a

a = - 24.3056²/250

a = - 2.363 m/s²

Now, force = mass × acceleration

We are given mass = 975 kg

Thus;

Force = 975 x (-2.363)

Force = 2303.925 N in the negative x-direction

B) formula for kinetic energy is

KE = ½mv²

KE = ½(975)(24.3056)²

= 287996.568288 J

Work done on impact = F x 2

Thus;

2F = 287996.568288

F = 287996.568288/2

F ≈ 143998.28 N

C) Ratio = Force on car/braking force = 143998.284/2303.925 = 62.5

3 0

3 years ago